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Lecture Notes in Differential Equations - Bruce E. Shapiro

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355<br />

Similarly, we can express a unit impulse centered at t 0 by a right shift, as<br />

δ a (t − t 0 ), and an <strong>in</strong>f<strong>in</strong>ite unite spike as δ(t − t 0 ).<br />

Figure 32.6: Unit impulse of width a at the orig<strong>in</strong> (left). Sequence of<br />

sharper and sharper impulses on the right, with smaller and smaller a<br />

values.<br />

1 2a<br />

5<br />

a<br />

a<br />

4<br />

3<br />

2<br />

1<br />

0<br />

2 1 0 1 2<br />

The Laplace transform of the unit impulse is<br />

[ ]<br />

1<br />

L[δ a (t − t 0 )] = L<br />

2a (U(t + a − t 0) − U(t − a − t 0 ))<br />

(32.222)<br />

= 1<br />

2a [L[U(t + a − t 0)] − L[U(t − a − t 0 )]] (32.223)<br />

= e(a−t0)s<br />

2as<br />

− e−(a+t0)s<br />

2as<br />

= e −t0s eas − e −as<br />

2as<br />

−t0s s<strong>in</strong>h as<br />

= e<br />

as<br />

(32.224)<br />

(32.225)<br />

(32.226)<br />

To get the Laplace transform of the delta function we take the limit as<br />

a → 0,<br />

−t0s s<strong>in</strong>h as<br />

L[δ(t − t 0 )] = lim e<br />

a→0 as<br />

(32.227)<br />

S<strong>in</strong>ce the right hand side → 0/0 we can use L‘Hopital’s rule from calculus,<br />

L[δ(t − t 0 )] = e −t0s a cosh as<br />

lim<br />

a→0 a<br />

(32.228)<br />

= e −t0s lim cosh as<br />

a→0<br />

(32.229)<br />

= e −t0s (32.230)

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