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Lecture Notes in Differential Equations - Bruce E. Shapiro

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194 LESSON 22. NON-HOMOG. EQS.W/ CONST. COEFF.<br />

Derivation of General Solution. We are now ready to f<strong>in</strong>d a general<br />

formula for the solution of<br />

ay ′′ + by ′ + cy = f(t) (22.67)<br />

where a ≠ 0, for any function f(t). We beg<strong>in</strong> by divid<strong>in</strong>g by a,<br />

y ′′ + By ′ + Cy = q(t) (22.68)<br />

where B = b/a, C = c/a, and q(t) = f(t)/a. By the factorization theorem<br />

(theorem (22.4)), (22.68) is equivalent to<br />

(D − r 1 )(D − r 2 )y = q(t) (22.69)<br />

where<br />

r 1,2 = 1 2<br />

(<br />

−B ± √ )<br />

B 2 − 4C<br />

(22.70)<br />

Def<strong>in</strong><strong>in</strong>g<br />

z = (D − r 2 )y = y ′ − r 2 y (22.71)<br />

equation (22.69) becomes<br />

(D − r 1 )z = q(t) (22.72)<br />

or equivalently,<br />

z ′ − r 1 z = q(t) (22.73)<br />

This is a first order l<strong>in</strong>ear ODE <strong>in</strong> z(t) with <strong>in</strong>tegrat<strong>in</strong>g factor<br />

(∫ )<br />

µ(t) = exp −r 1 dt = e −r1t (22.74)<br />

and the solution of (22.73) is<br />

z = 1<br />

µ(t)<br />

Us<strong>in</strong>g (22.71) this becomes<br />

(∫<br />

q(t)µ(t)dt + C 1<br />

)<br />

(22.75)<br />

y − r 2 y = p(t) (22.76)<br />

where<br />

p(t) = 1 (∫<br />

µ(t)<br />

q(t)µ(t)dt + C 1<br />

)<br />

Equation (22.76) is a first order l<strong>in</strong>ear ODE <strong>in</strong> y(t); its solution is<br />

y(t) = 1 (∫<br />

)<br />

p(t)ν(t)dt + C 2<br />

ν(t)<br />

(22.77)<br />

(22.78)

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