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Lecture Notes in Differential Equations - Bruce E. Shapiro

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165<br />

3. If f(t) = e rt and r is a root of the characteristic equation, but is not<br />

a repeated root, try<br />

y P = Ate rt (19.16)<br />

4. If f(t) = e rt and r is a repeated root of the characteristic equation,<br />

try<br />

y P = At 2 e rt (19.17)<br />

5. If f(t) = α s<strong>in</strong> ωt + β cos ωt, where α, β, ω ∈ R, and neither s<strong>in</strong> ωt nor<br />

cos ωt are solutions of the homogeneous equation, try<br />

y P = A cos ωt + B s<strong>in</strong> ωt (19.18)<br />

If (19.18) is a solution of the homogeneous equation, <strong>in</strong>stead try<br />

y P = t(A cos ωt + B s<strong>in</strong> ωt) (19.19)<br />

6. If f is a product of polynomials, exponentials, and/or s<strong>in</strong>es and<br />

cos<strong>in</strong>es, use a product of polynomials, exponentials, and/or s<strong>in</strong>es and<br />

cos<strong>in</strong>es. If any of the terms <strong>in</strong> the product is a solution of the homogeneous<br />

equation, multiply the entire solution by t or t 2 , whichever<br />

ensures that no terms <strong>in</strong> the guess are a solution of Ly = 0.<br />

Example 19.2. Solve<br />

The characteristic equation is<br />

hence<br />

y ′′ + y ′ − 6y = 2t (19.20)<br />

r 2 + r − 6 = (r − 2)(r + 3) = 0 (19.21)<br />

y H = C 1 e 2t + C 2 e −3t (19.22)<br />

S<strong>in</strong>ce the forc<strong>in</strong>g function (right-hand side of the equation) is 2t we try a<br />

particular function of<br />

y P = At + B (19.23)<br />

Differentiat<strong>in</strong>g,<br />

Substitut<strong>in</strong>g back <strong>in</strong>to the differential equation,<br />

y P ′ = A (19.24)<br />

y P ′′ = 0 (19.25)<br />

0 + A − 6(At + B) = 6t (19.26)<br />

−6At + A + B = 6t (19.27)

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