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Lecture Notes in Differential Equations - Bruce E. Shapiro

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132 LESSON 15. LINEAR OPERATORS AND VECTOR SPACES<br />

Def<strong>in</strong>ition 15.4. If y, z are both elements of a vector space V, and A and<br />

B are any numbers, we call<br />

a L<strong>in</strong>ear Comb<strong>in</strong>ation of y and z<br />

w = Ay + Bz (15.41)<br />

Example 15.8. If v = (1, 0, 3) and w = (5, −3, 12) are vectors <strong>in</strong> Euclidean<br />

3 space, then for any numbers A and B,<br />

u = Av + Bw = A(1, 0, 3) + B(5, −3, 12) = (A + 5B, −3B, 3A + 12B)<br />

(15.42)<br />

is a l<strong>in</strong>ear comb<strong>in</strong>ation of v and w.<br />

The closure property of vector spaces is sometimes stated as follow<strong>in</strong>g: Any<br />

l<strong>in</strong>ear comb<strong>in</strong>ation of vectors is an element of the same vector<br />

space. For example, we can create l<strong>in</strong>ear comb<strong>in</strong>ations of functions and<br />

we know that they are also <strong>in</strong> the same vector space.<br />

Example 15.9. Let f(t) = 3 s<strong>in</strong> t, g(t) = t 2 − 4t be functions <strong>in</strong> the vector<br />

space V of real valued functions. Then if A and B are any real numbers,<br />

h(t) = Af(t) + Bg(t) (15.43)<br />

= A s<strong>in</strong> t + B(t 2 − 4t) (15.44)<br />

is a l<strong>in</strong>ear comb<strong>in</strong>ation of the functions f and g. S<strong>in</strong>ce V is a vector space,<br />

h is also <strong>in</strong> V.<br />

Example 15.10. Let V be the vector space consist<strong>in</strong>g of real functions on<br />

the real numbers. Then differentiation, def<strong>in</strong>ed by<br />

D(y) = dy(t)<br />

dt<br />

(15.45)<br />

is a l<strong>in</strong>ear operator. To see that both properties hold let y(t) and z(t) be<br />

functions (e.g., y, z ∈ V) and let c be a constant. Then<br />

D(y + z) =<br />

d(y(t) + z(t)<br />

dt<br />

= dy(t)<br />

dt<br />

D(cy) = d(cy(t)<br />

dt<br />

Hence D is a l<strong>in</strong>ear operator.<br />

+ dz(t)<br />

dt<br />

= c dy(t)<br />

dt<br />

= D(y) + D(z) (15.46)<br />

= cD(y) (15.47)

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