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Lecture Notes in Differential Equations - Bruce E. Shapiro

Lecture Notes in Differential Equations - Bruce E. Shapiro

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108 LESSON 12. EXISTENCE OF SOLUTIONS*<br />

where the last step follows from the Lipshitz condition. Tak<strong>in</strong>g limits<br />

∫ t<br />

lim |F (t) − φ n+1(t)| ≤ lim K |φ(s) − φ n (s)| ds (12.66)<br />

n→∞ n→∞<br />

t 0<br />

But s<strong>in</strong>ce φ n → φ,<br />

∫ t ∣<br />

|F (t) − φ(t)| ≤ K<br />

φ(s) − φ ( s) ∣ ds = 0 (12.67)<br />

t 0<br />

S<strong>in</strong>ce the left hand side is an absolute value it must also be greater then or<br />

equal to zero:<br />

0 ≤ |F (t) − φ(t)| ≤ 0 (12.68)<br />

Hence<br />

|F (t) − φ(t)| = 0 =⇒ F (t) = φ(t) (12.69)<br />

Thus φ satisfies the <strong>in</strong>itial value problem.

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