2005 paper 2 solution
2005 paper 2 solution
2005 paper 2 solution
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6. y =<br />
24<br />
x<br />
2<br />
y = 24x −1<br />
y =<br />
when x = 4<br />
dy =<br />
2<br />
−12x −3<br />
y = 12<br />
dx<br />
dy −12<br />
=<br />
dx<br />
3<br />
( x)<br />
24<br />
(4)<br />
dy −12 =<br />
dx<br />
3<br />
(4)<br />
dy 12 = −<br />
dx 8<br />
dy 3 = −<br />
dx 2<br />
P(4,12) m =<br />
y – b = m(x – a)<br />
y – 12 =<br />
3<br />
− (x – 4)<br />
2<br />
2y – 24 = –3x + 12<br />
3x + 2y = 36<br />
3<br />
−<br />
2<br />
7. log 4 (5 – x) – log 4 (3 – x) = 2<br />
(5 − x)<br />
log 4<br />
(3 − x)<br />
4 2 =<br />
16 =<br />
= 2<br />
(5 − x)<br />
(3 − x)<br />
(5 − x)<br />
(3 − x)<br />
16(3 – x) = 5 – x<br />
48 – 16x = 5 – x<br />
43 = 15x<br />
43 = x<br />
15<br />
Solutions by MAitchison www.mathsroom.co.uk
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