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ON UNIQUE SOLVABILITY OF THE INITIAL VALUE PROBLEM FOR ...

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Unique Solvability of the Non-Linear Cauchy Problem 49<br />

Theorem 1. Let there exist linear operators φ 0 , φ 1 : D([a, b], R n ) →<br />

L 1 ([a, b], R n ), φ i = (φ ik ) n k=1 , i = 0, 1, satisfying the inclusions<br />

φ 0 ∈ S a ([a, b], R n ), φ 0 + φ 1 ∈ S a ([a, b], R n ) (6)<br />

and such that the inequalities<br />

∣ (fk u)(t) − (f k v)(t) − φ 0k (u − v)(t) ∣ ∣ ≤ φ1k (u − v)(t), k = 1, 2, . . . , n, (7)<br />

are true for arbitrary absolutely continuous functions u = (u k ) n k=1 and v =<br />

(v k ) n k=1 from [a, b] to Rn possessing the properties<br />

u k (a) = v k (a), u k (t) ≥ v k (t) for t ∈ [a, b], k = 1, 2, . . . , n. (8)<br />

Then the Cauchy problem (1), (2) is uniquely solvable for arbitrary real<br />

c k , k = 1, 2, . . . , n.<br />

Theorem 2. Assume that there exist positive linear operators g i =<br />

(g ik ) n i=1 : D([a, b], Rn ) → L 1 ([a, b], R n ), i = 0, 1, such that the inequalities<br />

∣ (fk u)(t) − (f k v)(t) + g 1k (u − v)(t) ∣ ∣ ≤ g0k (u − v)(t), k = 1, 2, . . . , n, (9)<br />

hold on [a, b] for any vector functions u = (u k ) n k=1 and v = (v k) n k=1 from<br />

D([a, b], R n ) with the properties (8). Moreover, let the inclusions<br />

g 0 + (1 − 2θ)g 1 ∈ S a ([a, b], R n ), −θg 1 ∈ S a ([a, b], R n ) (10)<br />

be true.<br />

Then the initial value problem (1), (2) has a unique solution for all c k ,<br />

k = 1, 2, . . . , n.<br />

Corollary 1. Let there exist positive linear operators g i = (g ik ) n k=1 :<br />

D([a, b], R n ) → L 1 ([a, b], R n ), i = 0, 1, satisfying the condition (9) for arbitrary<br />

absolutely continuous functions u = (u k ) n k=1 and v = (v k) n k=1 with the<br />

properties (8) and, moreover, such that the inclusions<br />

g 0 ∈ S a ([a, b], R n ), − 1 2 g 1 ∈ S a ([a, b], R n ) (11)<br />

hold.<br />

Then the initial value problem (1), (2) has a unique solution for any c k ,<br />

k = 1, 2, . . . , n.<br />

Corollary 2. Let there exist positive linear operators g i = (g ik ) n k=1 :<br />

D([a, b], R n ) → L 1 ([a, b], R n ), i = 0, 1, satisfying the condition (9) for arbitrary<br />

absolutely continuous functions u = (u k ) n k=1 and v = (v k) n k=1<br />

with the<br />

properties (8) and, moreover, such that the inclusions<br />

g 0 + 1 2 g 1 ∈ S a ([a, b], R n ), − 1 4 g 1 ∈ S a ([a, b], R n ) (12)<br />

are true.<br />

Then the problem (1), (2) has a unique solution for any c k , k = 1, 2, . . . , n.

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