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v2009.01.01 - Convex Optimization

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E.3. SYMMETRIC IDEMPOTENT MATRICES 649<br />

E.2.1<br />

Universal projector characteristic<br />

Although projection is not necessarily orthogonal and R(P )̸⊥ R(I − P ) in<br />

general, still for any projector P and any x∈ R m<br />

Px + (I − P )x = x (1782)<br />

must hold where R(I − P ) = N(P ) is the algebraic complement of R(P).<br />

The algebraic complement of closed convex cone K , for example, is the<br />

negative dual cone −K ∗ . (1900)<br />

E.3 Symmetric idempotent matrices<br />

When idempotent matrix P is symmetric, P is an orthogonal projector. In<br />

other words, the direction of projection of point x∈ R m on subspace R(P )<br />

is orthogonal to R(P ) ; id est, for P 2 =P ∈ S m and projection Px∈ R(P )<br />

Px − x ⊥ R(P ) in R m (1783)<br />

Perpendicularity is a necessary and sufficient condition for orthogonal<br />

projection on a subspace. [92,4.9]<br />

A condition equivalent to (1783) is: Norm of direction x −Px is the<br />

infimum over all nonorthogonal projections of x on R(P ) ; [215,3.3] for<br />

P 2 =P ∈ S m , R(P )= R(A) , matrices A,B, Z and positive integer k as<br />

defined for (1762), and given x∈ R m<br />

‖x − Px‖ 2 = ‖x − AA † x‖ 2 = inf<br />

B∈R n×k ‖x − A(A † + BZ T )x‖ 2 (1784)<br />

The infimum is attained for R(B)⊆ N(A) over any affine subset of<br />

nonorthogonal projectors (1764) indexed by k .<br />

Proof is straightforward: The vector 2-norm is a convex function. Setting<br />

gradient of the norm-square to 0, applyingD.2,<br />

(<br />

A T ABZ T − A T (I − AA † ) ) xx T A = 0<br />

⇔<br />

(1785)<br />

A T ABZ T xx T A = 0<br />

because A T = A T AA † . Projector P =AA † is therefore unique; the<br />

minimum-distance projector is the orthogonal projector, and vice versa.

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