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v2009.01.01 - Convex Optimization

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570 APPENDIX A. LINEAR ALGEBRA<br />

A.7.2<br />

0 entry<br />

If a positive semidefinite matrix A = [A ij ] ∈ R n×n has a 0 entry A ii on its<br />

main diagonal, then A ij + A ji = 0 ∀j . [235,1.3.1]<br />

Any symmetric positive semidefinite matrix having a 0 entry on its main<br />

diagonal must be 0 along the entire row and column to which that 0 entry<br />

belongs. [134,4.2.8] [176,7.1, prob.2]<br />

A.7.3 0 eigenvalues theorem<br />

This theorem is simple, powerful, and widely applicable:<br />

A.7.3.0.1 Theorem. Number of 0 eigenvalues.<br />

For any matrix A∈ R m×n<br />

rank(A) + dim N(A) = n (1469)<br />

by conservation of dimension. [176,0.4.4]<br />

For any square matrix A∈ R m×m , the number of 0 eigenvalues is at least<br />

equal to dim N(A)<br />

dim N(A) ≤ number of 0 eigenvalues ≤ m (1470)<br />

while the eigenvectors corresponding to those 0 eigenvalues belong to N(A).<br />

[287,5.1] A.16<br />

For diagonalizable matrix A (A.5), the number of 0 eigenvalues is<br />

precisely dim N(A) while the corresponding eigenvectors span N(A). The<br />

real and imaginary parts of the eigenvectors remaining span R(A).<br />

A.16 We take as given the well-known fact that the number of 0 eigenvalues cannot be less<br />

than the dimension of the nullspace. We offer an example of the converse:<br />

A =<br />

⎡<br />

⎢<br />

⎣<br />

1 0 1 0<br />

0 0 1 0<br />

0 0 0 0<br />

1 0 0 0<br />

dim N(A) = 2, λ(A) = [0 0 0 1] T ; three eigenvectors in the nullspace but only two are<br />

independent. The right-hand side of (1470) is tight for nonzero matrices; e.g., (B.1) dyad<br />

uv T ∈ R m×m has m 0-eigenvalues when u ∈ v ⊥ .<br />

⎤<br />

⎥<br />

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