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v2009.01.01 - Convex Optimization

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7.2. SECOND PREVALENT PROBLEM: 523<br />

7.2.2.7 Cumulative summary of rank heuristics<br />

We have studied the perturbation method of rank reduction in4.3, as<br />

well as the trace heuristic (convex envelope method7.2.2.1.1) and log det<br />

heuristic in7.2.2.4. There is another good contemporary method called<br />

LMIRank [247] based on alternating projection (E.10) that does not solve<br />

the ball packing problem presented in5.4.2.2.3.<br />

7.2.2.7.1 Example. Rank regularization enforcing affine dimension.<br />

We apply the convex iteration method from4.4.1 to numerically solve an<br />

instance of Problem 2; a method empirically superior to the foregoing convex<br />

envelope and log det heuristics.<br />

Unidimensional scaling, [89] a historically practical application of<br />

multidimensional scaling (5.12), entails solution of an optimization problem<br />

having local minima whose multiplicity varies as the factorial of point-list<br />

cardinality. Geometrically, it means finding a list constrained to lie in one<br />

affine dimension. In terms of point list, the nonconvex problem is: given<br />

nonnegative symmetric matrix H = [h ij ] ∈ S N ∩ R N×N<br />

+ (1262) whose entries<br />

h ij are all known,<br />

minimize<br />

{x i ∈R}<br />

N∑<br />

(|x i − x j | − h ij ) 2 (1213)<br />

i , j=1<br />

called a raw stress problem [46, p.34] which has an implicit constraint on<br />

dimensional embedding of points {x i ∈ R , i=1... N}. This problem has<br />

proven NP-hard; e.g., [64].<br />

As always, we first transform variables to distance-square D ∈ S N h ; so we<br />

begin with convex problem (1264) on page 517<br />

minimize − tr(V (D − 2Y )V )<br />

D , Y<br />

[ ]<br />

dij y ij<br />

subject to<br />

≽ 0 ,<br />

y ij<br />

h 2 ij<br />

Y ∈ S N h<br />

D ∈ EDM N<br />

rankV T N DV N = 1<br />

N ≥ j > i = 1... N −1<br />

(1281)<br />

that becomes equivalent to (1213) by making explicit the constraint on affine<br />

dimension via rank. The iteration is formed by moving the dimensional

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