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v2009.01.01 - Convex Optimization

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426 CHAPTER 5. EUCLIDEAN DISTANCE MATRIX<br />

D(X) = D(X[0 √ 2V N ]) = D(Q p [0 √ ΛQ T ]) = D([0 √ ΛQ T ])<br />

(1039)<br />

This suggests a way to find EDM D given −V T N DV N ; (confer (918))<br />

[<br />

0<br />

D =<br />

δ ( −VN TDV )<br />

N<br />

] [<br />

1 T + 1 0 δ ( −VN TDV ) ] T<br />

N<br />

5.12.2 0 geometric center. V<br />

[ 0 0<br />

T<br />

− 2<br />

0 −VN TDV N<br />

(818)<br />

Alternatively, we may perform reconstruction using instead the auxiliary<br />

matrix V (B.4.1), corresponding to the polyhedron<br />

P − α c (1040)<br />

whose geometric center has been translated to the origin. Redimensioning<br />

diagonalization factors Q, Λ∈R N×N and unknown Q p ∈ R n×N , (941)<br />

−V DV = 2V X T XV ∆ = Q √ ΛQ T pQ p<br />

√<br />

ΛQ<br />

T ∆ = QΛQ T (1041)<br />

where the geometrically centered generating list constitutes (confer (1037))<br />

XV = 1 √<br />

2<br />

Q p<br />

√<br />

ΛQ T ∈ R n×N<br />

= [x 1 − 1 N X1 x 2 − 1 N X1 x 3 − 1 N X1 · · · x N − 1 N X1 ] (1042)<br />

where α c = 1 N X1. (5.5.1.0.1) The simplest choice for Q p is [I 0 ]∈ R r×N .<br />

Now EDM D can be uniquely made from the list found, by calculating:<br />

(798)<br />

]<br />

D(X) = D(XV ) = D( 1 √<br />

2<br />

Q p<br />

√<br />

ΛQ T ) = D( √ ΛQ T ) 1 2<br />

(1043)<br />

This EDM is, of course, identical to (1039). Similarly to (818), from −V DV<br />

we can find EDM D ; (confer (905))<br />

D = δ(−V DV 1 2 )1T + 1δ(−V DV 1 2 )T − 2(−V DV 1 2 ) (824)

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