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v2009.01.01 - Convex Optimization

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4.1. CONIC PROBLEM 251<br />

In any SDP feasibility problem, an SDP feasible solution with the lowest<br />

rank must be an extreme point of the feasible set. Thus, there must exist<br />

an SDP objective function such that this lowest-rank feasible solution<br />

uniquely optimizes it. −Ye, 2006 [206,2.4] [207]<br />

Rank of a sum of members F +G in Lemma 2.9.2.6.1 and location of<br />

a difference F −G in2.9.2.9.1 similarly hold for S 3 + and S 3 + .<br />

Euclidean distance from any particular rank-3 positive semidefinite<br />

matrix (in the cone interior) to the closest rank-2 positive semidefinite<br />

matrix (on the boundary) is generally less than the distance to the<br />

closest rank-1 positive semidefinite matrix. (7.1.2)<br />

distance from any point in ∂S 3 + to int S 3 + is infinitesimal (2.1.7.1.1)<br />

distance from any point in ∂S 3 + to int S 3 + is infinitesimal<br />

faces of S 3 + correspond to faces of S 3 + (confer Table 2.9.2.3.1)<br />

k dim F(S+) 3 dim F(S 3 +) dim F(S 3 + ∋ rank-k matrix)<br />

0 0 0 0<br />

boundary 1 1 1 1<br />

2 2 3 3<br />

interior 3 3 6 6<br />

Integer k indexes k-dimensional faces F of S 3 + . Positive semidefinite<br />

cone S 3 + has four kinds of faces, including cone itself (k = 3,<br />

boundary + interior), whose dimensions in isometrically isomorphic<br />

R 6 are listed under dim F(S 3 +). Smallest face F(S 3 + ∋ rank-k matrix)<br />

that contains a rank-k positive semidefinite matrix has dimension<br />

k(k + 1)/2 by (204).<br />

For A equal to intersection of m hyperplanes having independent<br />

normals, and for X ∈ S 3 + ∩ A , we have rankX ≤ m ; the analogue<br />

to (245).<br />

Proof. With reference to Figure 70: Assume one (m = 1) hyperplane<br />

A = ∂H intersects the polyhedral cone. Every intersecting plane<br />

contains at least one matrix having rank less than or equal to 1 ; id est,<br />

from all X ∈ ∂H ∩ S 3 + there exists an X such that rankX ≤ 1. Rank 1<br />

is therefore an upper bound in this case.

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