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v2009.01.01 - Convex Optimization

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2.13. DUAL CONE & GENERALIZED INEQUALITY 189<br />

Applying algorithm (425) we get<br />

[ ]<br />

Γ ∗ 1 Γ ∗ 2 Γ ∗ 3 Γ ∗ 4<br />

⎡<br />

= 1 ⎢<br />

4⎣<br />

1 2 3 2<br />

1 2 −1 −2<br />

1 −2 −1 2<br />

−3 −2 −1 −2<br />

⎤<br />

⎥<br />

⎦ (429)<br />

whose rank is 3, and is the known result; 2.73 a conically independent set<br />

of generators for that pointed section of the dual cone K ∗ in aff K ; id est,<br />

K ∗ ∩ aff K .<br />

<br />

2.13.11.0.3 Example. Dual of proper polyhedral K in R 4 .<br />

Given conically independent generators for a full-dimensional pointed closed<br />

convex cone K<br />

X = [ Γ 1 Γ 2 Γ 3 Γ 4 Γ 5 ] =<br />

⎡<br />

⎢<br />

⎣<br />

1 1 0 1 0<br />

−1 0 1 0 1<br />

0 −1 0 1 0<br />

0 0 −1 −1 0<br />

⎤<br />

⎥<br />

⎦ (430)<br />

we count 5!/((5 −4)! 4!)=5 component simplices. Applying algorithm (425),<br />

we find the six extreme directions of dual cone K ∗<br />

⎡<br />

⎤<br />

1 0 0 1 1 1<br />

[<br />

]<br />

Γ ∗ 1 Γ ∗ 2 Γ ∗ 3 Γ ∗ 4 Γ ∗ 5 Γ ∗ 6 = ⎢ 1 0 0 1 0 0<br />

⎥<br />

⎣ 1 0 −1 0 −1 1 ⎦ (431)<br />

1 −1 −1 1 0 0<br />

which means, (2.13.6.1) this proper polyhedral K = cone(X) has six<br />

(three-dimensional) facets, whereas dual proper polyhedral cone K ∗ has only<br />

five.<br />

We can check this result (431) by reversing the process; we find<br />

6!/((6 −4)! 4!) − 3=12 component simplices in the dual cone. 2.74 Applying<br />

algorithm (425) to those simplices returns a conically independent set of<br />

generators for K equivalent to (430).<br />

<br />

2.73 These calculations proceed so as to be consistent with [97,6]; as if the ambient vector<br />

space were proper subspace aff K whose dimension is 3. In that ambient space, K may<br />

be regarded as a proper cone. Yet that author (from the citation) erroneously states<br />

dimension of the ordinary dual cone to be 3 ; it is, in fact, 4.<br />

2.74 Three combinations of four dual extreme directions are linearly dependent.

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