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v2009.01.01 - Convex Optimization

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186 CHAPTER 2. CONVEX GEOMETRY<br />

2.13.11 Proper nonsimplicial K , dual, X fat full-rank<br />

Since conically dependent columns can always be removed from X to<br />

construct K or to determine K ∗ (Wıκımization), then assume we are given<br />

a set of N conically independent generators (2.10) of an arbitrary proper<br />

polyhedral cone K in R n arranged columnar in X ∈ R n×N such that N > n<br />

(fat) and rankX = n . Having found formula (374) to determine the dual of<br />

a simplicial cone, the easiest way to find a vertex-description of proper dual<br />

cone K ∗ is to first decompose K into simplicial parts K i so that K = ⋃ K i . 2.72<br />

Each component simplicial cone in K corresponds to some subset of n<br />

linearly independent columns from X . The key idea, here, is how the<br />

extreme directions of the simplicial parts must remain extreme directions of<br />

K . Finding the dual of K amounts to finding the dual of each simplicial part:<br />

2.13.11.0.1 Theorem. Dual cone intersection. [286,2.7]<br />

Suppose proper cone K ⊂ R n equals the union of M simplicial cones K i whose<br />

extreme directions all coincide with those of K . Then proper dual cone K ∗<br />

is the intersection of M dual simplicial cones K ∗ i ; id est,<br />

M⋃<br />

M⋂<br />

K = K i ⇒ K ∗ = K ∗ i (418)<br />

i=1<br />

Proof. For X i ∈ R n×n , a complete matrix of linearly independent<br />

extreme directions (p.130) arranged columnar, corresponding simplicial K i<br />

(2.12.3.1.1) has vertex-description<br />

i=1<br />

K i = {X i c | c ≽ 0} (419)<br />

⋄<br />

Now suppose,<br />

K =<br />

M⋃<br />

K i =<br />

i=1<br />

M⋃<br />

{X i c | c ≽ 0} (420)<br />

i=1<br />

2.72 That proposition presupposes, of course, that we know how to perform simplicial<br />

decomposition efficiently; also called “triangulation”. [262] [147,3.1] [148,3.1] Existence<br />

of multiple simplicial parts means expansion of x∈ K like (365) can no longer be unique<br />

because the number N of extreme directions in K exceeds dimension n of the space.

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