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v2009.01.01 - Convex Optimization

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160 CHAPTER 2. CONVEX GEOMETRY<br />

2.13.4.2.2 Exercise. Test of discretized dual generalized inequalities.<br />

Test Theorem 2.13.4.2.1 on Figure 49(a) using the extreme directions as<br />

generators.<br />

<br />

From the discretized membership theorem we may further deduce a more<br />

surgical description of closed convex cone that prescribes only a finite number<br />

of halfspaces for its construction when polyhedral: (Figure 48(a))<br />

K = {x ∈ R n | 〈γ ∗ , x〉 ≥ 0 for all γ ∗ ∈ G(K ∗ )} (331)<br />

K ∗ = {y ∈ R n | 〈γ , y〉 ≥ 0 for all γ ∈ G(K)} (332)<br />

2.13.4.2.3 Exercise. Partial order induced by orthant.<br />

When comparison is with respect to the nonnegative orthant K = R n + , then<br />

from the discretized membership theorem it directly follows:<br />

x ≼ z ⇔ x i ≤ z i ∀i (333)<br />

Generate simple counterexamples demonstrating that this equivalence with<br />

entrywise inequality holds only when the underlying cone inducing partial<br />

order is the nonnegative orthant.<br />

<br />

2.13.5 Dual PSD cone and generalized inequality<br />

The dual positive semidefinite cone K ∗ is confined to S M by convention;<br />

S M ∗<br />

+<br />

∆<br />

= {Y ∈ S M | 〈Y , X〉 ≥ 0 for all X ∈ S M + } = S M + (334)<br />

The positive semidefinite cone is self-dual in the ambient space of symmetric<br />

matrices [53, exmp.2.24] [35] [170,II]; K = K ∗ .<br />

Dual generalized inequalities with respect to the positive semidefinite cone<br />

in the ambient space of symmetric matrices can therefore be simply stated:<br />

(Fejér)<br />

X ≽ 0 ⇔ tr(Y T X) ≥ 0 for all Y ≽ 0 (335)<br />

Membership to this cone can be determined in the isometrically isomorphic<br />

Euclidean space R M2 via (31). (2.2.1) By the two interpretations in2.13.1,<br />

positive semidefinite matrix Y can be interpreted as inward-normal to a<br />

hyperplane supporting the positive semidefinite cone.

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