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v2009.01.01 - Convex Optimization

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134 CHAPTER 2. CONVEX GEOMETRY<br />

From the definition it follows that any single hyperplane through the<br />

origin, or any halfspace partially bounded by a hyperplane through the origin<br />

is a polyhedral cone. The most familiar example of polyhedral cone is any<br />

quadrant (or orthant,2.1.3) generated by Cartesian half-axes. Esoteric<br />

examples of polyhedral cone include the point at the origin, any line through<br />

the origin, any ray having the origin as base such as the nonnegative real<br />

line R + in subspace R , polyhedral flavors of the (proper) Lorentz cone<br />

(confer (160))<br />

{[ ]<br />

}<br />

x<br />

K l = ∈ R n × R | ‖x‖<br />

t<br />

l ≤ t , l=1 or ∞ (260)<br />

any subspace, and R n .<br />

Figure 20.<br />

More examples are illustrated in Figure 44 and<br />

2.12.2 Vertices of convex polyhedra<br />

By definition, a vertex (2.6.1.0.1) always lies on the relative boundary of a<br />

convex polyhedron. [194, def.115/6, p.358] In Figure 16, each vertex of the<br />

polyhedron is located at the intersection of three or more facets, and every<br />

edge belongs to precisely two facets [25,VI.1, p.252]. In Figure 20, the only<br />

vertex of that polyhedral cone lies at the origin.<br />

The set of all polyhedral cones is clearly a subset of convex polyhedra and<br />

a subset of convex cones. Not all convex polyhedra are bounded; evidently,<br />

neither can they all be described by the convex hull of a bounded set of<br />

points as defined in (78). Hence we propose a universal vertex-description of<br />

polyhedra in terms of that same finite-length list X (68):<br />

2.12.2.0.1 Definition. <strong>Convex</strong> polyhedra, vertex-description.<br />

(confer2.8.1.1.1) Denote the truncated a-vector<br />

[ ]<br />

ai<br />

a i:l = .<br />

a l<br />

(261)<br />

By discriminating a suitable finite-length generating list (or set) arranged<br />

columnar in X ∈ R n×N , then any particular polyhedron may be described<br />

P = { Xa | a T 1:k1 = 1, a m:N ≽ 0, {1... k} ∪ {m ... N} = {1... N} } (262)<br />

where 0≤k ≤N and 1≤m≤N+1. Setting k=0 removes the affine<br />

equality condition. Setting m=N+1 removes the inequality. △

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