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sparse image representation via combined transforms - Convex ...

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56 CHAPTER 3. IMAGE TRANSFORMS AND IMAGE FEATURES<br />

assume that the basis {ψ(x − k) :k ∈ Z} is orthonormal:<br />

∫<br />

ψ(x)ψ(x − k)dx = δ(k), k ∈ Z. (3.24)<br />

Since ψ(x) isinV 1 , there must exist a real-valued sequence {g(n) :n ∈ Z} such that<br />

ψ(x) = ∑ n∈Z<br />

g(n)φ(2x − n). (3.25)<br />

Since functional subspace V 0 and functional subspace W 0 are orthogonal, we have<br />

∫<br />

ψ(x)φ(x − k) =0, k ∈ Z. (3.26)<br />

From (3.20) and (3.21), we have<br />

∑<br />

h(n)h(n − 2k) =2δ(k), k ∈ Z. (3.27)<br />

n∈Z<br />

From (3.24) and (3.25), we have<br />

∑<br />

g(n)g(n − 2k) =2δ(k), k ∈ Z. (3.28)<br />

n∈Z<br />

From (3.26), (3.21) and (3.25), we have<br />

∑<br />

g(n)h(n − 2k) =0, k ∈ Z. (3.29)<br />

n∈Z<br />

Actually, if relations (3.27), (3.28) and (3.29) hold, then the sequence g can only be the<br />

reverse of the sequence h modulated by the sequence {(−1) n : n ∈ Z}. The following<br />

theorem provides a formal description.<br />

Theorem 3.6 (Quadratic Mirror Filter) If two sequences {h(n) :n ∈ Z} and {g(n) :<br />

n ∈ Z} satisfy the relations listed in (3.27), (3.28) and (3.29), then the sequence {g(n) :<br />

n ∈ Z} is uniquely determined by the sequence {h(n) :n ∈ Z} <strong>via</strong><br />

∀n ∈ Z, g(n) =(−1) n h(1 + 2k − n), (3.30)<br />

where k is a pre-determined integer.

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