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3.1. DCT AND HOMOGENEOUS COMPONENTS 49<br />

Suppose C 2 and C ′ 2<br />

are the two Hankel matrices<br />

⎛<br />

C 2 =<br />

⎜<br />

⎝<br />

⎞<br />

c 1 c 2 ... c N−1 c N<br />

c 2 c 3 ... c N c N−1<br />

. .<br />

. .<br />

, (3.16)<br />

c N−1 c N ... c 3 c 2<br />

⎟<br />

⎠<br />

c N c N−1 ... c 2 c 1<br />

. ..<br />

⎛<br />

C 2 ′ =<br />

⎜<br />

⎝<br />

c ′ 1 c ′ 2 ... c ′ N−1<br />

0<br />

c ′ 2 c ′ 3 ... 0 −c ′ N−1<br />

. .<br />

. ..<br />

. .<br />

c ′ N−1<br />

0 ... −c ′ 3 −c ′ 2<br />

0 −c ′ N−1<br />

... −c ′ 2 −c ′ 1<br />

⎞<br />

. (3.17)<br />

⎟<br />

⎠<br />

Note that C 2 is counter symmetric (if a {i,j} is the {i, j}th element of the matrix, then<br />

a {i,j} = a {N+1−i,N+1−j} ,for i, j =1, 2,... ,N)andC 2 ′ is counter antisymmetric (if a {i,j} is<br />

the {i, j}th element of the matrix, then a {i,j} = −a {N+1−i,N+1−j} ,fori, j =1, 2,... ,N).<br />

Let D denote a down-right-shift operator on matrix, such that<br />

⎛<br />

D(C 2 )=<br />

⎜<br />

⎝<br />

⎞<br />

c 0 c 1 ... c N−2 c N−1<br />

c 1 c 2 ... c N−1 c N<br />

. .<br />

. .<br />

, (3.18)<br />

c N−2 c N−1 ... c 4 c 3<br />

⎟<br />

⎠<br />

c N−1 c N ... c 3 c 2<br />

. ..<br />

and<br />

⎛<br />

D(C 2)=<br />

′ ⎜<br />

⎝<br />

c ′ 0 c ′ 1 ... c ′ N−2<br />

c ′ N−1<br />

c ′ 1 c ′ 2 ... c ′ N−1<br />

0<br />

. .<br />

. ..<br />

. .<br />

c ′ N−2<br />

c ′ N−1<br />

... −c ′ 4 −c ′ 3<br />

c ′ N−1<br />

0 ... −c ′ 3 −c ′ 2<br />

⎞<br />

. (3.19)<br />

⎟<br />

⎠<br />

Note that D(C 2 )andD(C 2 ′ ) are still Hankel matrices.

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