sparse image representation via combined transforms - Convex ...
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sparse image representation via combined transforms - Convex ...
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3.1. DCT AND HOMOGENEOUS COMPONENTS 49<br />
Suppose C 2 and C ′ 2<br />
are the two Hankel matrices<br />
⎛<br />
C 2 =<br />
⎜<br />
⎝<br />
⎞<br />
c 1 c 2 ... c N−1 c N<br />
c 2 c 3 ... c N c N−1<br />
. .<br />
. .<br />
, (3.16)<br />
c N−1 c N ... c 3 c 2<br />
⎟<br />
⎠<br />
c N c N−1 ... c 2 c 1<br />
. ..<br />
⎛<br />
C 2 ′ =<br />
⎜<br />
⎝<br />
c ′ 1 c ′ 2 ... c ′ N−1<br />
0<br />
c ′ 2 c ′ 3 ... 0 −c ′ N−1<br />
. .<br />
. ..<br />
. .<br />
c ′ N−1<br />
0 ... −c ′ 3 −c ′ 2<br />
0 −c ′ N−1<br />
... −c ′ 2 −c ′ 1<br />
⎞<br />
. (3.17)<br />
⎟<br />
⎠<br />
Note that C 2 is counter symmetric (if a {i,j} is the {i, j}th element of the matrix, then<br />
a {i,j} = a {N+1−i,N+1−j} ,for i, j =1, 2,... ,N)andC 2 ′ is counter antisymmetric (if a {i,j} is<br />
the {i, j}th element of the matrix, then a {i,j} = −a {N+1−i,N+1−j} ,fori, j =1, 2,... ,N).<br />
Let D denote a down-right-shift operator on matrix, such that<br />
⎛<br />
D(C 2 )=<br />
⎜<br />
⎝<br />
⎞<br />
c 0 c 1 ... c N−2 c N−1<br />
c 1 c 2 ... c N−1 c N<br />
. .<br />
. .<br />
, (3.18)<br />
c N−2 c N−1 ... c 4 c 3<br />
⎟<br />
⎠<br />
c N−1 c N ... c 3 c 2<br />
. ..<br />
and<br />
⎛<br />
D(C 2)=<br />
′ ⎜<br />
⎝<br />
c ′ 0 c ′ 1 ... c ′ N−2<br />
c ′ N−1<br />
c ′ 1 c ′ 2 ... c ′ N−1<br />
0<br />
. .<br />
. ..<br />
. .<br />
c ′ N−2<br />
c ′ N−1<br />
... −c ′ 4 −c ′ 3<br />
c ′ N−1<br />
0 ... −c ′ 3 −c ′ 2<br />
⎞<br />
. (3.19)<br />
⎟<br />
⎠<br />
Note that D(C 2 )andD(C 2 ′ ) are still Hankel matrices.