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sparse image representation via combined transforms - Convex ...

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B.6. MISCELLANEOUS 169<br />

The function ρ is<br />

ρ(x) =<br />

=<br />

=<br />

∫<br />

∫ p<br />

−p<br />

ˆρ(ξ)e 2π√ −1ξx dξ<br />

cos(2πξx)dξ +<br />

sin(πx) + sin(2πpx)<br />

2πx<br />

∫ 1/2<br />

p<br />

[<br />

cos(2πξx) 1+cos<br />

1<br />

1 − (1 − 2p) 2 x 2 .<br />

]<br />

2π(ξ − p)<br />

dξ<br />

1 − 2p<br />

When p is 1/2, we get the sinc function in case one. When p is 0, we get the ρ function<br />

in case two. When p = 1 4<br />

, the Figure B.9 shows how the function ρ and function ˆρ<br />

look.<br />

When p is 1/4 and function ρ(·) only takes integer values, unlike the two previous<br />

cases, the function ρ does not have finite support.<br />

(a) ρ when p = 0.25<br />

2.5<br />

(b) ρ_hat is 50% taped.<br />

1<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

0<br />

−0.2<br />

2<br />

1.5<br />

1<br />

0.5<br />

0<br />

−0.5<br />

−0.4<br />

−5 0 5<br />

x<br />

−1<br />

−2 0 2<br />

ξ<br />

Figure B.9: Fifty percent tapered window function in (b) and its counterpart in time domain<br />

in (a).

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