10.03.2015 Views

sparse image representation via combined transforms - Convex ...

sparse image representation via combined transforms - Convex ...

sparse image representation via combined transforms - Convex ...

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

140 APPENDIX A. DIRECT EDGELET TRANSFORM<br />

(a) Wood Grain Image<br />

(b) Largest−10000 coeff. (log)<br />

(c) Largest−20000 coeff.<br />

100<br />

100<br />

100<br />

200<br />

200<br />

200<br />

300<br />

300<br />

300<br />

400<br />

400<br />

400<br />

500<br />

100 200 300 400 500<br />

500<br />

100 200 300 400 500<br />

500<br />

100 200 300 400 500<br />

(d) Edgelet trans. coeff.(best−1500000/1839104)<br />

(e) Largest−40000 coeff.<br />

(f) Largest−80000 coeff.<br />

210<br />

100<br />

100<br />

200<br />

200<br />

200<br />

190<br />

300<br />

300<br />

180<br />

400<br />

400<br />

170<br />

5 10 15<br />

x 10 5<br />

500<br />

100 200 300 400 500<br />

500<br />

100 200 300 400 500<br />

Figure A.3: Edgelet transform of the wood grain <strong>image</strong>: (a) is the original; (d) is the sorted<br />

coefficients; (b), (c), (e) and (f) are reconstructions based on the largest 1 × 10 4 ,2× 10 4 ,<br />

4 × 10 4 ,8× 10 4 coefficients, respectively.<br />

so when the <strong>image</strong> is a gray-scale <strong>image</strong>, I(i, j) is the gray scale at point (i, j). A 2-D<br />

function f is defined in the following way: for i, j =1, 2,... ,N,ifx and y fall in the<br />

cell ((i − 1)/N, i/N ] × ((j − 1)/N, j/N ], then f(x, y) =I(i, j). Suppose e is an edgelet as<br />

described in Section A.1. The edgelet transform of I corresponding to e is the integration<br />

of the function f divided by the length of e:<br />

E(I,e)=<br />

∫<br />

e f<br />

length(e) .<br />

Note this integration is a weighted sum of I(i, j) where the edgelet e intersects the square<br />

((i − 1)/N, i/N ] × ((j − 1)/N, j/N ]. The weight of I(i, j) depends on the fraction of e in<br />

the cell ((i − 1)/N, i/N ] × ((j − 1)/N, j/N ].

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!