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sparse image representation via combined transforms - Convex ...

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4.12. PROOFS 99<br />

4.12.2 Proof of Theorem 4.1<br />

We will prove convergence first, and then prove that the limiting distribution is x ′ .<br />

When γ takes all the real positive values, (x(γ),γ) forms a continuous and differentiable<br />

trajectory in R N+1 .Letx i γ denote the ith element of x(γ). By the first-order condition, we<br />

have<br />

⎛ ⎞<br />

∂ ¯ρ(x 1 γ ,γ)<br />

∂x<br />

0=−2Φ T (y − Φx(γ)) + λ ⎜ ⎟<br />

⎝ ⎠ .<br />

.<br />

∂ ¯ρ(x N γ ,γ)<br />

∂x<br />

Taking d<br />

dγ<br />

Since<br />

on both sides, we have<br />

0=2Φ T Φ dx(γ)<br />

dγ<br />

⎛<br />

+ λ ⎜<br />

⎝<br />

∂ 2 ¯ρ(x 1 γ ,γ)<br />

∂γ∂x<br />

∂ 2 ¯ρ(x N γ ,γ)<br />

∂γ∂x<br />

+ dx1 γ<br />

dγ<br />

.<br />

+ dxN γ<br />

dγ<br />

∂ 2 ¯ρ(x 1 γ ,γ)<br />

∂x∂x<br />

∂ 2 ¯ρ(x N γ ,γ)<br />

∂x∂x<br />

⎞<br />

⎟<br />

⎠ .<br />

∂ 2 ¯ρ(x, γ)<br />

∂γ∂x<br />

= xe −γ|x| ,<br />

and<br />

∂ 2 ¯ρ(x, γ)<br />

∂x∂x<br />

= γe −γ|x| ,<br />

we have<br />

−2Φ T Φ dx(γ)<br />

dγ<br />

⎛<br />

= λ ⎜<br />

⎝<br />

⎞<br />

x 1 γe −γ|x1γ| + dx1 γ<br />

γ|<br />

dγ γe−γ|x1 .<br />

⎟<br />

⎠ .<br />

x N γ e −γ|xN γ | + dxN γ<br />

dγ γe−γ|xN γ |<br />

Based on Assumption 2, suppose that the kth entry of vector dx(γ)<br />

dγ<br />

the maximum amplitude of the vector:<br />

dx(γ)<br />

∥ dγ ∥ = − dxk γ<br />

∞<br />

dγ .<br />

is negative and takes

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