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98 CHAPTER 4. COMBINED IMAGE REPRESENTATION<br />

and its corresponding version with a Lagrangian multiplier λ,<br />

(RIA λ )<br />

x (k+1) = argmin ‖y − Φx‖ 2 2 + λ<br />

x<br />

N∑<br />

i=1<br />

|x i |<br />

|x (k)<br />

i<br />

| + δ .<br />

We know the following results.<br />

Theorem 4.2 Suppose we add one more constraint on x: x i ≥ 0,i=1, 2,... ,N. The sequence<br />

generated by (RIA), {x (k)<br />

i<br />

,k =1, 2, 3,...}, converges in the sense that the difference<br />

of sequential elements goes to zero:<br />

|x (k+1)<br />

i<br />

− x (k)<br />

i<br />

|→0, as k → +∞.<br />

We learned this result from [95].<br />

Theorem 4.3 If the sequence {x (k)<br />

i<br />

,k = 1, 2, 3,...} generated by (RIA λ ) converges, it<br />

converges to a local minimum of (LO λ ).<br />

Some related works can be found in [36, 106]. There is also some ongoing research, for<br />

example, the work being carried out by Boyd, Lobo and Fazel in the Information Systems<br />

Laboratories, Stanford.<br />

4.12 Proofs<br />

4.12.1 Proof of Proposition 4.1<br />

When ̂x is the solution to the problem as in (4.2), the first order condition is<br />

0=λ∇ρ(x)+2Φ T Φx − 2Φ T y,<br />

where ∇ρ(x) is the gradient vector of ρ(x). Hence<br />

1<br />

2 λ∇ρ(x) =ΦT (y − Φx) . (4.15)<br />

Recall ρ(x) = ∑ N<br />

i=1 ¯ρ(x i). It’s easy to verify that ∀x i , |¯ρ ′ (x i )|≤1. Hence for the left-hand<br />

side of (4.15), we have ‖ 1 2 λ∇ρ(x)‖ ∞ ≤ λ 2<br />

. The bound (4.6) follows. ✷

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