MCS 351 ENGINEERING MATHEMATICS SOLUTION OF ...
MCS 351 ENGINEERING MATHEMATICS SOLUTION OF ...
MCS 351 ENGINEERING MATHEMATICS SOLUTION OF ...
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1-3 Uniform Convergence :<br />
1. Let<br />
∞∑<br />
(z − 2i) 2n and |z − 2i| ≤ 0.999. We know that<br />
n=0<br />
1<br />
1 − z = 1 + z + z2 + z 3 + . . .<br />
1<br />
∞<br />
1 − (z − 2i) 2 = ∑<br />
(z − 2i) 2n = 1 + (z − 2i) 2 + (z − 2i) 4 + (z − 2i) 6 + . . .<br />
n=0<br />
Because |z − 2i| ≤ 0.999, this serie converges uniformly.<br />
2. Let<br />
∞∑<br />
n=0<br />
z 2n+1<br />
(2n + 1)! and |z| ≤ 1010 .999. Since<br />
sinh z =<br />
∞∑<br />
n=0<br />
z 2n+1<br />
(2n + 1)! = z + z3<br />
3! + z5<br />
5! + . . .<br />
this Maclaurin series of sinh z converges uniformly on every bounded set.<br />
3. Let<br />
∞∑<br />
n=0<br />
π n<br />
n 4 z2n and |z| ≤ 0.56. From ratio test, we have<br />
lim L = lim<br />
n→∞ n→∞<br />
∣<br />
π n+1<br />
(n+1) 4<br />
π n<br />
n 4<br />
∣ ∣ = lim<br />
n→∞<br />
and |z| ≤ 0.56, this serie converges uniformly on everywhere.<br />
πn 4<br />
(n + 1) 4 = π > 1,<br />
9-11 Power series :<br />
9. Let<br />
∞∑ (z + 1 − 2i) n<br />
4 n . By ratio test, we get<br />
n=0<br />
lim L = lim<br />
n→∞ n→∞<br />
∣<br />
1<br />
4 ( n+1)<br />
1<br />
4 n ∣ ∣ = lim<br />
n→∞<br />
then we can say that this serie converges uniformly on everywhere.<br />
10. Let<br />
∞∑<br />
n=0<br />
(z − i) 2n<br />
. Since<br />
(2n)!<br />
cosh z =<br />
∞∑<br />
n=0<br />
1<br />
4 = 1 4 < 1,<br />
z 2n<br />
(2n)! = 1 + z2<br />
2! + z4<br />
4! + . . .<br />
this Taylor series of cosh z with center i converges uniformly on every bounded set.<br />
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