MCS 351 ENGINEERING MATHEMATICS SOLUTION OF ...
MCS 351 ENGINEERING MATHEMATICS SOLUTION OF ...
MCS 351 ENGINEERING MATHEMATICS SOLUTION OF ...
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
21.<br />
İf z = x + iy, then f(z) = Re2z = 2x is analytic.<br />
=⇒ ∫ C<br />
Re2zdz = 0.<br />
14.3<br />
1.We should use Cauchy’s integral formula to solve this question.<br />
We can sketch C : |z − i| = 2 as follows:<br />
∮<br />
C<br />
f(z)<br />
z−z 0<br />
dz = 2πif(z 0 )<br />
Let g(z) = z2 −4<br />
z 2 +4 .We know that z2 + 4 = (z − 2i)(z + 2i).<br />
z 0 − 2i = 0 ⇒ z 0 = 2i<br />
z 1 + 2i = 0 ⇒ z 1 = −2i<br />
C encloses the point z 0 = 2i but don’t encloses the point z 1 = −2i, where g(z) is not analytic. Let<br />
f(z) = z2 −4<br />
z+2i<br />
, D be the union of C and the interior part of C. f(z) is analytic in D. So we can use the<br />
formula.<br />
∮<br />
z 2 −4<br />
C z 2 +4 dz = ∮ z 2 −4<br />
C z+2i . 1<br />
z−2i dz = 2πi.f(2i) = 2πi. (2i)2 −4<br />
2i+2i<br />
= 2πi. 4i2 −4<br />
4i<br />
= 2πi. −8<br />
4i<br />
== −4π<br />
4. We sketch C : |z| = π/2 as follows:<br />
39