01.02.2015 Views

64 m kj izns'k jktf"kZ V.Mu eqDr fo'ofo|ky;] bykgkckn

64 m kj izns'k jktf"kZ V.Mu eqDr fo'ofo|ky;] bykgkckn

64 m kj izns'k jktf"kZ V.Mu eqDr fo'ofo|ky;] bykgkckn

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

26<br />

88<br />

m <strong>kj</strong> izns’k jktf"<strong>kZ</strong> V.<strong>Mu</strong> <strong>eqDr</strong> fo’ofo|ky;] <strong>bykgkckn</strong><br />

fo’k; % xf.kr<br />

Subject : Mathematics<br />

dkslZ “kh’<strong>kZ</strong>d % Advance Calculus<br />

Courset Title : Advance Calculus<br />

vf/kU;kl (Assignment) 2012-2013<br />

Lukrd dyk dk;ZØe<br />

Under Graduate Art Programme<br />

Section - A<br />

[k.M & d<br />

fo’k; dksM% ;w0th0,e0,e0<br />

Subject Code : UGMM<br />

dkslZ dksM % ;w0th0,e0,e0-07<br />

Course Code : UGMM-07<br />

vf/kdre vad % 30<br />

Maximum Marks:30<br />

vf/kdre vad % 18<br />

Max. Marks: 18<br />

uksV % nh<strong>kZ</strong> mRrjh; iz”uA vius iz”uksa ds mRrj 800 ls 1000 “kCnksa esa fy[ksaA lHkh<br />

iz”u vfuok;Z gSA<br />

Note : Long Answer Questions. Answer should be given in 800 to 1000 words.<br />

Answer all questions.<br />

1(a)<br />

(b)<br />

(<br />

x,<br />

y,<br />

z)<br />

Calculate the Jacobian<br />

for 3<br />

(<br />

r,<br />

q,<br />

z)<br />

tSdksfc;u Kkr djsaA<br />

x = r cosq, y = r sinq , z = z<br />

2 2<br />

x<br />

x<br />

Prove that F = TR ® TR defined by f(x,y) = ( e cos y,<br />

e sin y)<br />

is<br />

not invertible on the whole of TR 2 , but it is locally invertible at each point of<br />

TR 2 . 3<br />

2(a) Find<br />

ò ò<br />

D<br />

Kkr djsaA<br />

f ( x,<br />

y)<br />

dxdy where<br />

ìSiny<br />

f ( x,<br />

y)<br />

= í<br />

î y<br />

, y ¹ 0, y = 0<br />

3<br />

(b) Find the volume of the region lying in the first octant which is common to<br />

the two cylinders x 2 + y 2 = a 2 and x 2 + z 2 = a 2<br />

3<br />

ml ifj{ks= dk vk;ru Kkr djsa tks x 2 + y 2 = a 2 rFkk x 2 + z 2 = a 2 ds chp esa<br />

fLFkr gSA<br />

3(a) Evaluate<br />

lim x + cos x<br />

(i)<br />

x ® -¥ x + sin x<br />

3<br />

Kkr djsa<br />

lim 1<br />

(ii)<br />

x ® ¥ 1+ log( x - 2)<br />

(b) If A, B, C are the angles of a triangle such that 3<br />

2<br />

2<br />

2<br />

sin A + sin B + sin c = K<br />

dA tanC<br />

- tan B<br />

=<br />

dB tan A - tanC<br />

2<br />

2<br />

2<br />

;fn A, B, C ,d f=Hkqt ds dks.k gS rFkk sin A + sin B + sin c = K gks<br />

dA tanC<br />

- tan B<br />

rks fn[kk;sa =<br />

dB tan A - tanC<br />

Section - B<br />

[k.M & [k<br />

vf/kdre vad % 12<br />

Max. Marks: 12<br />

uksV % ykq mRrjh; iz”uA vius iz”uksa ds mRrj 200 ls 300 “kCnksa esa fy[ksaA lHkh<br />

iz”u vfuok;Z gSA<br />

Note : Short Answer Questions. Answer should be given in 200 to 300 words.<br />

Answer all questions.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!