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64 m kj izns'k jktf"kZ V.Mu eqDr fo'ofo|ky;] bykgkckn

64 m kj izns'k jktf"kZ V.Mu eqDr fo'ofo|ky;] bykgkckn

64 m kj izns'k jktf"kZ V.Mu eqDr fo'ofo|ky;] bykgkckn

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18<br />

83<br />

mRrj iznsk jktf<strong>kZ</strong> V.<strong>Mu</strong> <strong>eqDr</strong> <strong>fo'ofo|ky</strong>;] <strong>bykgkckn</strong><br />

vf/kU;kl (Assignment) l= 2012&13<br />

Lukrd dyk dk;ZØe<br />

Under Graduate Art Programme<br />

fo’k; % xf.kr<br />

Subject : Mathematics<br />

dkslZ “kh’<strong>kZ</strong>d % Calculus<br />

Course Title : Calculus-01<br />

Section - A<br />

[k.M & d<br />

fo’k; dksM% ;w0th0,e0,e0<br />

Subject Code : UGMM<br />

dkslZ dksM % ;w0th0,e0,e0-01<br />

Course Code : UGMM-01<br />

vf/kdre vad % 30<br />

Maximum Marks:30<br />

vf/kdre vad % 18<br />

Max. Marks:18<br />

uksV % All qestions ar compulsory<br />

Note : Section A is long Answer and Section B is Short Answer Questions.<br />

1(a)<br />

Evaluate<br />

Kkr djsaA<br />

lim<br />

x ® 0<br />

a<br />

æ tan<br />

x ÷ ö<br />

ç<br />

è ø<br />

2<br />

1/ x<br />

(b) Evaluate<br />

ò ( a - x)(<br />

x - b ) dx<br />

2<br />

b<br />

Kkr djsaA<br />

d<br />

tan x x<br />

(c) Find ((cos x)<br />

+ x )<br />

2<br />

dx<br />

Kkr djsaA<br />

2(a) State and prove Rolle's theorem. 3<br />

2<br />

2<br />

-1æ1-<br />

x<br />

(b) Differentiate<br />

÷ ö<br />

-1<br />

ç<br />

æ 2x<br />

ö<br />

cos with respect to tan<br />

2<br />

ç<br />

2<br />

÷<br />

è1+<br />

x ø<br />

è1-<br />

x ø<br />

2(a) jkWy izes; dks fy[kdj fl) djsaA<br />

(b)<br />

2<br />

-1æ<br />

1-<br />

x<br />

÷ ö<br />

-1<br />

ç<br />

æ 2x<br />

ö<br />

cos dks tan<br />

2 ç<br />

2<br />

÷<br />

è1+<br />

x ø è1-<br />

x ø<br />

ds lkis{k vodfyr djsaA<br />

3(a)<br />

2<br />

ìx<br />

ü<br />

ï - a x < aï<br />

ï<br />

a<br />

ï<br />

If F( x)<br />

= í0<br />

x = 0ýthen discuss the Continuity and<br />

ï 2<br />

ï<br />

ï<br />

a<br />

a - x > aï<br />

î x<br />

þ<br />

differentiability at x = a<br />

3<br />

(b)<br />

2 2 4 4 6 6 8 8<br />

2 x 2 x 2 x 2 x<br />

Show that cos 2x = 1-<br />

+ - + - - - - -<br />

2! 4! 6! 8!<br />

3<br />

2<br />

ìx<br />

ü<br />

ï - a x < aï<br />

ï<br />

a<br />

ï<br />

3(a) ;fn F( x)<br />

= í0<br />

x = 0ý<br />

rks x = a ij Fex)<br />

dh lR;rk<br />

ï 2<br />

ï<br />

ï<br />

a<br />

a - x > aï<br />

î x<br />

þ<br />

,oa vodyuh;rk Kkr djsaA<br />

2 2 4 4 6 6 8 8<br />

2 x 2 x 2 x 2 x<br />

(b) fn[kk;sa fd cos 2x<br />

= 1-<br />

+ - + - - - - - -<br />

2! 4! 6! 8!<br />

Section - B<br />

[k.M & [k<br />

vf/kdre vad % 12<br />

Max. Marks:12<br />

-<br />

4. If (sin 1 2<br />

2<br />

y = x)<br />

then show that (1 x ) y -(2n<br />

+ 1) xy -n<br />

y = 0 3<br />

-<br />

n+ 2<br />

n+<br />

1 n<br />

3

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