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Answer Key Math 1142 Fall 2005 Final Exam

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<strong>Answer</strong> <strong>Key</strong><br />

<strong>Math</strong> <strong>1142</strong><br />

<strong>Fall</strong> <strong>2005</strong> <strong>Final</strong> <strong>Exam</strong><br />

Multiple Choice Problems<br />

1. B<br />

2. D<br />

3. A<br />

4. C<br />

5. D<br />

6. E<br />

7. B<br />

8. A<br />

9. E<br />

10. C<br />

11. E<br />

12. B<br />

13. C<br />

14. B<br />

Written <strong>Answer</strong> Problems<br />

15. on [ −1 , 3 ] -- f ( 3 ) =<br />

absolute minimum<br />

3<br />

3<br />

is the absolute maximum,<br />

f (−1) = − 1 2<br />

is the<br />

16.<br />

a) intervals € of increase: ( −∞ , −2 ) , ( 2 , ∞ ) , interval € of decrease: ( −2 , 2 )<br />

b) inflection point at ( 0, 3 ) ; interval of upward concavity: ( 0 , ∞ ) ,<br />

interval of downward concavity: ( −∞ , 0 )<br />

c) local maximum at ( −2, 19 ) , local minimum at ( 2, −13 )<br />

d) see graph below<br />

17. y = ½ ln ( x 2 – 6x + 4 )<br />

18.<br />

a)<br />

dy<br />

dx = 2e−x (4 + 14x − 3x 2 ) (3x + 4 ) 4 b)<br />

1<br />

4 x 2 ln x − 1 8 x 2 + C<br />

19. maximum volume is 256<br />

€ 20.<br />

2 ( ln [ 3 + 2 3 ] − ln [ 3 ] ) or ln (7 + 4€<br />

3 )<br />

€<br />

(continued)


graph for Problem #16(d) –

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