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Chapter 11 Boundary layer theory

Chapter 11 Boundary layer theory

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<strong>11</strong>.1. STAGNATION POINT FLOW <strong>11</strong><br />

The above velocity and velocity gradients are inserted into the x momentum<br />

balance equation <strong>11</strong>.19, and divided throughout by (˙γx), to obtain,<br />

d 3 ( ) 2<br />

f df<br />

dη − + f d2 f<br />

3 dη dη + 1 = 0 (<strong>11</strong>.55)<br />

2<br />

The boundary conditions for f(η) can be obtained from the boundary conditions<br />

on the stream function <strong>11</strong>.45 and <strong>11</strong>.46 at the surface of the plate<br />

y = 0 (η = 0), and the condition <strong>11</strong>.47 in the limit y → ∞ (η → ∞).<br />

f(η) = 0 at η = 0 (<strong>11</strong>.56)<br />

df<br />

= 0 at η = 0 (<strong>11</strong>.57)<br />

dη<br />

f(η) → η for η → ∞ (<strong>11</strong>.58)<br />

The shear stress at the surface is given by,<br />

τ xy = µ ∂u x<br />

(<strong>11</strong>.59)<br />

∂y ∣ y=0<br />

= ρ(ν 1/2 ˙γ 3/2 x 1/2 ) d2 f<br />

dη 2 ∣ ∣∣∣∣η=0<br />

(<strong>11</strong>.60)<br />

Therefore, the shear stress at the surface increases as x 1/2 as the downsteam<br />

distance x increases.<br />

( The value of (d 2 f/dη 2 ) = 0.664 at η = 0 is obtained from the numerical<br />

solution of equation for f(η), and therefore the shear stress at the surface<br />

of the plate is,<br />

( ) νU<br />

3 1/2<br />

τ xy = 0.332ρ ∞<br />

(<strong>11</strong>.61)<br />

x<br />

The total force exerted on the plate, per unit length in the direction perpendicular<br />

to the flow, is determined by integrating equation the shear stress,<br />

F x =<br />

The ‘drag coefficient’ is defined as,<br />

∫ L<br />

0<br />

dx τ xy<br />

= 0.664ρ(νU 3 ∞ L)1/2 (<strong>11</strong>.62)<br />

C D =<br />

F x<br />

(ρU 2 ∞/2)L<br />

= 1.328Re −1/2<br />

L (<strong>11</strong>.63)

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