Exercise 3.3

Exercise 3.3 Exercise 3.3

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MA111: Prepared by Dr.Archara Pacheenburawana 41 Answer to Exercise 4.4 1. (a) 364 3 (b) −2 (c) 16 3 (d) 88 3 (e) 7 8 (f) 12 5 (g) 0 (h) 2 (i) Does not exist (j) 3 (k) ln3 (l) e+e −1 −2 (m) 28 ln2 (q) 5 2 (r) 2− √ 2 2 (s) − 11 6 (t) 10.7 (n) 3e 3 −12 (o) π2 9 +2√ 3 (p) π 2 2. (a) f ′ (x) = x 2 −3x+2 (b) g ′ (x) = √ 1+2x (c) g ′ (y) = y 2 siny (d) F ′ (x) = −cos(x 2 ) (e) f ′ (x) = (e −x4 +1)2x (f) f ′ (x) = −ln(x 2 +1) (g) h ′ (x) = −arctan(1/x)/x 2 (h) y ′ = cos√ x 2x (j) y ′ = 3x 7/2 sin(x 3 )−(sin √ x)/(2 4√ x) Evaluate the definite integral, if it exists. 1. 3. 5. 7. 9. 11. 13. 15. ∫ 2 0 ∫ 1 0 ∫ 1 0 ∫ 4 1 ∫ 3 (x−1) 25 dx 2. x 2 (1+2x 3 ) 5 dx 4. Exercise 4.5 ∫ 2 0 ∫ 1 −1 ∫ π (i) y ′ = 3(1−3x)3 1+(1−3x) 2 x √ x 2 +1dx x (x 2 +1) 2 dx 4cosx (sinx+1) 2 dx cosπxdx 6. π/2 √ 1 1+ 1 ∫ π/2 x 2 x dx 8. cotxdx dx 2x+3 0 ∫ π/3 0 ∫ 2 1 ∫ a 0 10. π/4 ∫ 4 ∫ sinx 13 cos 2 x dx 12. x √ x−1dx 14. x √ x 2 +a 2 dx (a > 0) 1 0 ∫ e 4 e x−1 √ x dx dx √ 3 (1+2x) 2 dx x √ lnx Answer to Exercise 4.5 1. 0 2. 5 3√ 5− 1 3 3. 81 4 4. 0 5. 0 6. −2 7. 4 √ 2 3 − 5√ 5 12 8. 1 2 ln2 9. 1 2 ln3 10. 8 3 11. 1 12. 3 13. 16 15 14. 2 15. 1 3 (2√ 2−1)a 3

MA111: Prepared by Dr.Archara Pacheenburawana 42 1. Find the area of the shaded region. Exercise 5.1 (a) y y = x 2 +1 −1 2 x (b) y y = x 2 +2 y = −x −1 2 x (c) y y = 2−x 2 y = x x 2. Find the area of the region bounded by the given curves. (a) y = x 2 +3, y = x, −1 ≤ x ≤ 1 (b) y = x 3 , y = x 2 −1, 1 ≤ x ≤ 3 (c) y = x+1, y = 9−x 2 , −1 ≤ x ≤ 2

MA111: Prepared by Dr.Archara Pacheenburawana 41<br />

Answer to <strong>Exercise</strong> 4.4<br />

1. (a) 364<br />

3<br />

(b) −2 (c) 16 3<br />

(d) 88<br />

3<br />

(e) 7 8<br />

(f) 12<br />

5<br />

(g) 0 (h) 2 (i) Does not exist<br />

(j) 3 (k) ln3 (l) e+e −1 −2 (m) 28<br />

ln2<br />

(q) 5 2<br />

(r) 2− √ 2<br />

2<br />

(s) − 11 6<br />

(t) 10.7<br />

(n) 3e 3 −12 (o) π2<br />

9 +2√ 3 (p) π 2<br />

2. (a) f ′ (x) = x 2 −3x+2 (b) g ′ (x) = √ 1+2x (c) g ′ (y) = y 2 siny<br />

(d) F ′ (x) = −cos(x 2 ) (e) f ′ (x) = (e −x4 +1)2x (f) f ′ (x) = −ln(x 2 +1)<br />

(g) h ′ (x) = −arctan(1/x)/x 2 (h) y ′ = cos√ x<br />

2x<br />

(j) y ′ = 3x 7/2 sin(x 3 )−(sin √ x)/(2 4√ x)<br />

Evaluate the definite integral, if it exists.<br />

1.<br />

3.<br />

5.<br />

7.<br />

9.<br />

11.<br />

13.<br />

15.<br />

∫ 2<br />

0<br />

∫ 1<br />

0<br />

∫ 1<br />

0<br />

∫ 4<br />

1<br />

∫ 3<br />

(x−1) 25 dx 2.<br />

x 2 (1+2x 3 ) 5 dx 4.<br />

<strong>Exercise</strong> 4.5<br />

∫ 2<br />

0<br />

∫ 1<br />

−1<br />

∫ π<br />

(i) y ′ = 3(1−3x)3<br />

1+(1−3x) 2<br />

x √ x 2 +1dx<br />

x<br />

(x 2 +1) 2 dx<br />

4cosx<br />

(sinx+1) 2 dx<br />

cosπxdx 6.<br />

π/2<br />

√<br />

1<br />

1+ 1 ∫ π/2<br />

x 2 x dx 8. cotxdx<br />

dx<br />

2x+3<br />

0<br />

∫ π/3<br />

0<br />

∫ 2<br />

1<br />

∫ a<br />

0<br />

10.<br />

π/4<br />

∫ 4<br />

∫<br />

sinx<br />

13<br />

cos 2 x dx 12.<br />

x √ x−1dx 14.<br />

x √ x 2 +a 2 dx (a > 0)<br />

1<br />

0<br />

∫ e 4<br />

e<br />

x−1<br />

√ x<br />

dx<br />

dx<br />

√<br />

3 (1+2x)<br />

2<br />

dx<br />

x √ lnx<br />

Answer to <strong>Exercise</strong> 4.5<br />

1. 0 2. 5 3√<br />

5−<br />

1<br />

3<br />

3. 81<br />

4<br />

4. 0 5. 0 6. −2 7.<br />

4 √ 2<br />

3<br />

− 5√ 5<br />

12<br />

8. 1 2 ln2 9. 1 2 ln3<br />

10.<br />

8<br />

3<br />

11. 1 12. 3 13. 16<br />

15<br />

14. 2 15. 1 3 (2√ 2−1)a 3

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