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<strong>MB31</strong> –Review <strong>Sheet</strong> 3 <strong>Answers</strong><br />
Name KEY<br />
1. In circle O, chords AB and CD intersect at E. If AE = 4, EB = 12, and ED = 16.<br />
Find the measure of CE .<br />
When two chords are drawn in a circle,<br />
the product of the segments of one chord is equal<br />
to the product of the segments of the other chord.<br />
AE • EB = CE • ED<br />
4• 12= x • 16<br />
48 = 16x<br />
3 = x<br />
Therefore CE = 3.<br />
2. Tangent PA and secant PBC are drawn to circle O from point P. If PB = 4, and BC = 5,<br />
find the measure of PA .<br />
When a tangent and a secant are drawn to a circle<br />
from the same external point, the product of the secant<br />
and it’s external segment is equal to the tangent squared.<br />
PC • PB = ( PA)<br />
(4 + 5) • 4 = x<br />
2<br />
2<br />
36 = x<br />
6 = x<br />
2<br />
Therefore PA = 6.<br />
3. Secants PBC and PDE are drawn to circle O from point P. If PBC = 20, PB = 5, and DE = 21,<br />
find the measure of PDE .<br />
When two secants are drawn to a circle from the same<br />
external point, the product of one secant and it’s<br />
external segment is equal to the product of the other<br />
secant and it’s external segment.<br />
PC • PB = PE • PD<br />
20• 5 = xx ( + 21)<br />
2<br />
100 = + 21<br />
x<br />
x<br />
x<br />
2<br />
+ 21x− 100 = 0<br />
( x+ 25)( x− 4) = 0<br />
x=− 25 x=<br />
4<br />
Reject<br />
Since x = 4 the measure of PDE = x + 21 = 4 + 21 = 25<br />
4. Identify each graph as of one of the following: line, circle, ellipse, parabola, hyperbola, equilateral hyperbola<br />
a)<br />
2 2<br />
2x<br />
= 16− y Ellipse<br />
h)<br />
2<br />
4x<br />
y 25<br />
+ = Parabola<br />
b)<br />
2 2 2<br />
x + 5= 21−2y − x Circle<br />
i)<br />
y<br />
2<br />
= ( x− 3) Parabola<br />
c)<br />
d)<br />
e)<br />
x<br />
x<br />
− 4y<br />
= 36 Hyperbola<br />
2 2<br />
2<br />
− 4y<br />
= 36 Parabola<br />
2 2<br />
2x<br />
4y<br />
36<br />
+ = Ellipse<br />
f) xy = 12<br />
Equilateral Hyperbola<br />
g) x+ y = 12<br />
Line<br />
j)<br />
k)<br />
l)<br />
m)<br />
5<br />
x = Equilateral Hyperbola<br />
y<br />
2 2<br />
2y<br />
= 6− x Ellipse<br />
2 2<br />
6x<br />
= 12+ 2y<br />
Hyperbola<br />
2 2<br />
36 − x = y Circle<br />
n) 4xy = − 16 Equilateral Hyperbola
5. Sketch the graph:<br />
a)<br />
2 2<br />
( x 5) ( y 1) 4<br />
+ + − = b)<br />
2 2<br />
( x+<br />
2) y<br />
+ = 1<br />
c) xy = 10<br />
9 36<br />
Circle with center at (-5, 1) Ellipse with center at (-2, 0) Equilateral hyperbola<br />
includes points: includes points: in Quadrants I and III<br />
(-7, 1), (-3, 1), (-5, 3), (-5, -1) (-5, 0), (1, 0), (-2, 6), (-2, -6)<br />
c)<br />
2 2<br />
x y<br />
− = 1<br />
d)<br />
36 16<br />
y = −<br />
2<br />
2x<br />
6<br />
Hyperbola<br />
Parabola<br />
with x-intercepts at x =± 6<br />
opens upward with y − int =− 6<br />
6. An ellipse has its center at (-1, 2). Its minor axis is vertical and has a length of 8. Its major axis is horizontal<br />
and has a length of 10. Write an equation for this ellipse.<br />
2 2<br />
( x−h) ( y−k)<br />
+ = 1<br />
2 2<br />
a b<br />
2 2<br />
( x+ 1) ( y−2)<br />
+ = 1<br />
25 16<br />
Since the length of the axes are given, you need to<br />
divide them by two first and then square them to find<br />
the denominators.<br />
7. Because Kelly’s coach believes that every<br />
player should get an equal opportunity to play, she<br />
varies the playing time so that it is inversely<br />
proportional to the number of players who show up<br />
for a game. When the whole team of 16 players<br />
attends, each player has 18 minutes of play time.<br />
How many players must be absent for Kelly to play<br />
for 24 minutes<br />
a) 12 b) 8 c) 6 d) 4<br />
(18)(16) = 24x<br />
288 = 24x<br />
x = 12<br />
Since 12 players must be<br />
present, 4 players must<br />
be absent.<br />
8. When David drives to Melissa’s college to visit<br />
her, his travel time varies inversely as his speed.<br />
If he drives at 56 miles/hour, he arrives in 3 hours.<br />
How many minutes would he save if he traveled at<br />
60 miles/hour<br />
a) 80 b) 40 c) 28 d) 12<br />
(56)(3) = 60x<br />
168 = 60x<br />
x = 2.8 hours<br />
He would save 0.2 hours,<br />
which is 12 minutes.
9. If p varies inversely as q, find the missing<br />
value in the table:<br />
p 40 30 20<br />
q 9 x 18<br />
a) 4.5 b) 12 c) 15 d) 16<br />
(40)(9) = 30x<br />
360 = 30x<br />
x = 12<br />
10. If a varies directly as b, and a = 28 when<br />
b = 8, what is a when b = 14<br />
a) 49 b) 16 c) 3.5 d) 98<br />
28 a<br />
=<br />
8 14<br />
8a = 392<br />
a = 49<br />
11. Each of the graphs is a transformation of the graph of<br />
y<br />
2<br />
= x . Find an equation for each of the functions.<br />
y =− ( x+<br />
4)<br />
2<br />
y = + +<br />
2<br />
( x 1) 2<br />
y = − − +<br />
2<br />
( x 3) 2<br />
12. Write an equation of the graph<br />
y<br />
2<br />
= x after the following transformation:<br />
a) Shifted 2 units to the left and 4 units up.<br />
b) Reflected in the x-axis, shifted 5 units down and 1 unit to the right.<br />
y = + +<br />
2<br />
( x 2) 4<br />
y =− − −<br />
2<br />
( x 1) 5