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MB31 –Review Sheet 3 Answers

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<strong>MB31</strong> –Review <strong>Sheet</strong> 3 <strong>Answers</strong><br />

Name KEY<br />

1. In circle O, chords AB and CD intersect at E. If AE = 4, EB = 12, and ED = 16.<br />

Find the measure of CE .<br />

When two chords are drawn in a circle,<br />

the product of the segments of one chord is equal<br />

to the product of the segments of the other chord.<br />

AE • EB = CE • ED<br />

4• 12= x • 16<br />

48 = 16x<br />

3 = x<br />

Therefore CE = 3.<br />

2. Tangent PA and secant PBC are drawn to circle O from point P. If PB = 4, and BC = 5,<br />

find the measure of PA .<br />

When a tangent and a secant are drawn to a circle<br />

from the same external point, the product of the secant<br />

and it’s external segment is equal to the tangent squared.<br />

PC • PB = ( PA)<br />

(4 + 5) • 4 = x<br />

2<br />

2<br />

36 = x<br />

6 = x<br />

2<br />

Therefore PA = 6.<br />

3. Secants PBC and PDE are drawn to circle O from point P. If PBC = 20, PB = 5, and DE = 21,<br />

find the measure of PDE .<br />

When two secants are drawn to a circle from the same<br />

external point, the product of one secant and it’s<br />

external segment is equal to the product of the other<br />

secant and it’s external segment.<br />

PC • PB = PE • PD<br />

20• 5 = xx ( + 21)<br />

2<br />

100 = + 21<br />

x<br />

x<br />

x<br />

2<br />

+ 21x− 100 = 0<br />

( x+ 25)( x− 4) = 0<br />

x=− 25 x=<br />

4<br />

Reject<br />

Since x = 4 the measure of PDE = x + 21 = 4 + 21 = 25<br />

4. Identify each graph as of one of the following: line, circle, ellipse, parabola, hyperbola, equilateral hyperbola<br />

a)<br />

2 2<br />

2x<br />

= 16− y Ellipse<br />

h)<br />

2<br />

4x<br />

y 25<br />

+ = Parabola<br />

b)<br />

2 2 2<br />

x + 5= 21−2y − x Circle<br />

i)<br />

y<br />

2<br />

= ( x− 3) Parabola<br />

c)<br />

d)<br />

e)<br />

x<br />

x<br />

− 4y<br />

= 36 Hyperbola<br />

2 2<br />

2<br />

− 4y<br />

= 36 Parabola<br />

2 2<br />

2x<br />

4y<br />

36<br />

+ = Ellipse<br />

f) xy = 12<br />

Equilateral Hyperbola<br />

g) x+ y = 12<br />

Line<br />

j)<br />

k)<br />

l)<br />

m)<br />

5<br />

x = Equilateral Hyperbola<br />

y<br />

2 2<br />

2y<br />

= 6− x Ellipse<br />

2 2<br />

6x<br />

= 12+ 2y<br />

Hyperbola<br />

2 2<br />

36 − x = y Circle<br />

n) 4xy = − 16 Equilateral Hyperbola


5. Sketch the graph:<br />

a)<br />

2 2<br />

( x 5) ( y 1) 4<br />

+ + − = b)<br />

2 2<br />

( x+<br />

2) y<br />

+ = 1<br />

c) xy = 10<br />

9 36<br />

Circle with center at (-5, 1) Ellipse with center at (-2, 0) Equilateral hyperbola<br />

includes points: includes points: in Quadrants I and III<br />

(-7, 1), (-3, 1), (-5, 3), (-5, -1) (-5, 0), (1, 0), (-2, 6), (-2, -6)<br />

c)<br />

2 2<br />

x y<br />

− = 1<br />

d)<br />

36 16<br />

y = −<br />

2<br />

2x<br />

6<br />

Hyperbola<br />

Parabola<br />

with x-intercepts at x =± 6<br />

opens upward with y − int =− 6<br />

6. An ellipse has its center at (-1, 2). Its minor axis is vertical and has a length of 8. Its major axis is horizontal<br />

and has a length of 10. Write an equation for this ellipse.<br />

2 2<br />

( x−h) ( y−k)<br />

+ = 1<br />

2 2<br />

a b<br />

2 2<br />

( x+ 1) ( y−2)<br />

+ = 1<br />

25 16<br />

Since the length of the axes are given, you need to<br />

divide them by two first and then square them to find<br />

the denominators.<br />

7. Because Kelly’s coach believes that every<br />

player should get an equal opportunity to play, she<br />

varies the playing time so that it is inversely<br />

proportional to the number of players who show up<br />

for a game. When the whole team of 16 players<br />

attends, each player has 18 minutes of play time.<br />

How many players must be absent for Kelly to play<br />

for 24 minutes<br />

a) 12 b) 8 c) 6 d) 4<br />

(18)(16) = 24x<br />

288 = 24x<br />

x = 12<br />

Since 12 players must be<br />

present, 4 players must<br />

be absent.<br />

8. When David drives to Melissa’s college to visit<br />

her, his travel time varies inversely as his speed.<br />

If he drives at 56 miles/hour, he arrives in 3 hours.<br />

How many minutes would he save if he traveled at<br />

60 miles/hour<br />

a) 80 b) 40 c) 28 d) 12<br />

(56)(3) = 60x<br />

168 = 60x<br />

x = 2.8 hours<br />

He would save 0.2 hours,<br />

which is 12 minutes.


9. If p varies inversely as q, find the missing<br />

value in the table:<br />

p 40 30 20<br />

q 9 x 18<br />

a) 4.5 b) 12 c) 15 d) 16<br />

(40)(9) = 30x<br />

360 = 30x<br />

x = 12<br />

10. If a varies directly as b, and a = 28 when<br />

b = 8, what is a when b = 14<br />

a) 49 b) 16 c) 3.5 d) 98<br />

28 a<br />

=<br />

8 14<br />

8a = 392<br />

a = 49<br />

11. Each of the graphs is a transformation of the graph of<br />

y<br />

2<br />

= x . Find an equation for each of the functions.<br />

y =− ( x+<br />

4)<br />

2<br />

y = + +<br />

2<br />

( x 1) 2<br />

y = − − +<br />

2<br />

( x 3) 2<br />

12. Write an equation of the graph<br />

y<br />

2<br />

= x after the following transformation:<br />

a) Shifted 2 units to the left and 4 units up.<br />

b) Reflected in the x-axis, shifted 5 units down and 1 unit to the right.<br />

y = + +<br />

2<br />

( x 2) 4<br />

y =− − −<br />

2<br />

( x 1) 5

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