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A spatially resolved study of ionized regions in galaxies at different ...

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160 Appendix A<br />

where c=0.434C. This value is the redden<strong>in</strong>g constant, and is found <strong>in</strong> the liter<strong>at</strong>ure as<br />

c(Hβ), the logarithmic ext<strong>in</strong>ction <strong>at</strong> Hβ (F Hβ = F Hβ0 10 −c ). We can rearrange equ<strong>at</strong>ion A.2<br />

as<br />

F λ = F λ0 10 −c(λ) = F λ0 10 −c(Hβ)(1+g(λ))<br />

(A.3)<br />

where g(λ) = f(λ) - f(Hβ) and c(Hβ) the logarithmic ext<strong>in</strong>ction <strong>at</strong> Hβ, which can be written<br />

as c(Hβ) = 0.4A Hβ . Compar<strong>in</strong>g equ<strong>at</strong>ion A.3 with A.1 and tak<strong>in</strong>g <strong>in</strong>to account the redden<strong>in</strong>g<br />

curve ζ(λ),<br />

g(λ) = A λ<br />

A β<br />

− 1 =<br />

ζ(λ)<br />

ζ(λ Hβ ) − 1<br />

(A.4)<br />

F<strong>in</strong>ally, we can write the logarithmic ext<strong>in</strong>ction <strong>at</strong> any wavelength c(λ) as a function <strong>of</strong><br />

the redden<strong>in</strong>g curve<br />

c(λ) = c(Hβ)(1 + g(λ)) = c(Hβ) ζ(λ)<br />

ζ(λ Hβ )<br />

(A.5)<br />

We can also write the constant <strong>of</strong> redden<strong>in</strong>g <strong>in</strong> terms <strong>of</strong> the color excess<br />

c(Hβ) = 0.4A Hβ = 0.4ζ(λ Hβ )R V E(B − V )<br />

(A.6)<br />

Tak<strong>in</strong>g <strong>in</strong>to account the redden<strong>in</strong>g law <strong>of</strong> Cardelli et al. (1989) and a value <strong>of</strong> R V = 3.1,<br />

we obta<strong>in</strong> A Hβ /A V = ζ(λ Hβ ) = 1.164, which allows to write the redden<strong>in</strong>g constant as a<br />

function <strong>of</strong> the color excess as c(Hβ) = 1.443 E(B-V).<br />

Another way <strong>of</strong> estim<strong>at</strong><strong>in</strong>g the ext<strong>in</strong>ction is by rel<strong>at</strong><strong>in</strong>g the visual ext<strong>in</strong>ction to the<br />

observed r<strong>at</strong>io <strong>of</strong> two l<strong>in</strong>es. This method is useful when only Hα and Hβ are available. The<br />

rel<strong>at</strong>ion is given by:<br />

and re-arrang<strong>in</strong>g it gives<br />

F Hα<br />

F Hβ<br />

= F Hα0 · 10 −0.4A Hα<br />

F Hβ0 · 10 −0.4A Hβ<br />

= F Hα0<br />

F Hβ0<br />

· 10 0.4 A Hβ −A Hα<br />

A V<br />

·A V<br />

(A.7)<br />

A V = 2.5 ·<br />

( )<br />

FHα /F<br />

log Hβ<br />

10 F Hα0 /F Hβ0<br />

A Hβ −A Hα<br />

A V<br />

(A.8)

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