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Slides Chapter 1. Measure Theory and Probability

Slides Chapter 1. Measure Theory and Probability

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<strong>1.</strong>4. PROBABILITY MEASURES<br />

For this, we will first consider the collection of intervals<br />

C = {(a,b],(−∞,b],(a,+∞) : a < b}. (<strong>1.</strong>1)<br />

We start by assigning values of P to intervals from C, by ensuring<br />

that P is σ-additive on C. Then, we consider the algebra F obtained<br />

by doing finite unions of disjoint intervals from C <strong>and</strong> we<br />

extend P to F. The extended function will be a probability measureon(IR,F).<br />

Finally,thereisauniqueextensionofaprobability<br />

measure from F to σ(F) = B, see the following propositions.<br />

Proposition <strong>1.</strong>7 Consider the collection of all finite unions of<br />

disjoint intervals from C in (<strong>1.</strong>1),<br />

{ n<br />

}<br />

⋃<br />

F = A i : A i ∈ C, A i disjoint .<br />

Then F is an algebra.<br />

i=1<br />

Next we extend P from C to F as follows.<br />

Proposition <strong>1.</strong>8 (Extensionof theprobabilityfunction)<br />

(a) For all A ∈ F, since A = ⋃ n<br />

i=1 (a i,b i ], with a i ,b i ∈ IR ∪<br />

{−∞,+∞}, let us define<br />

n∑<br />

P 1 (A) = P(a i ,b i ].<br />

i=1<br />

Then, P 1 is a probability measure over (IR,F).<br />

(b) For all A ∈ C, it holds that P(A) = P 1 (A).<br />

Observe that B = σ(F). Finally, can we extend P from F to<br />

B = σ(F)? If the answer is positive, is the extension unique? The<br />

next theorem gives the answer to these two questions.<br />

ISABEL MOLINA 17

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