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mohatta2015.pdf

signal processing from power amplifier operation control point of view

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84 LINEAR EQUALIZATION<br />

Substituting (4.96) into (4.95) gives<br />

£/ s h Ou O u Cv u h<br />

= E s h H C- 1 h=E s w» h h (4.97)<br />

We can also compute output SNR (ignoring ISI) by keeping only the noise component<br />

of C u . For the special case of root-Nyquist pulse shaping, symbol-spaced<br />

paths, and aligned symbol-spaced samples, the output SNR becomes<br />

L-\<br />

SNR 0 = (£ s /iV n )^| ft | 2 . (4.98)<br />

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