Renold Clutches & Couplings - casa sueca s.a.

Selection Examples
Example 1 Example 2
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Selection of 6 Cylinder Diesel Engine 750 kW at 900 rpm
driving a Centrifugal Pump.
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Selection of Induction Motor 800 kW at
1498 rpm driving a Rotary Pump.
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The coupling is flywheel mounted
Pump shaft diameter = dm
P = 750 kW n = 900 rpm
dm = 95 mm temp = 30°C
Fp = 1.7 Fm = 1.5
T NORM = (P/n) x 9549 Nm
= (750/900) x 9549 Nm
= 7.958 kNm
T MAX = T NORM (Fp + Fm)
= 7.958 (1.7 + 1.5)
= 25.466 kNm
The application is considered light industrial and RB type
coupling should be selected. Examination of RB catalogue
shows RB 3.86 as:
T Kmax = 27.4 kNm T KN = 9.159 kNm
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Motor shaft = dp Pump shaft = dm
P = 800 kW n = 1498 rpm
dp = 95 mm dm = 85 mm
temp = 30°C Fp = 0
Fm = 2
T NORM = (P/n) x 9549 Nm
= (800/1498) x 9549 Nm
= 5.1 kNm
T MAX = T NORM (Fp + Fm)
= 5.1 (0 + 2) kNm
= 10.2 kNm
The application requires a steel coupling (by customer
specification) and PM type coupling should be selected.
Examination of PM catalogue shows PM12 as:
T Kmax = 12 kNm
which satisfies the condition
which satisfies the condition
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T MAX < T Kmax (25.466 < 27.4) kNm
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T MAX < T Kmax (10.2 < 12.0) kNm
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T NORM