undergraduate prospectus 2011 - University of Engineering and ...

UNIVERSITY OF ENGINEERING AND TECHNOLOGY- TAXILA / UNDERGRAD PROSPECTUS 2011
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32.7. Merit Determined Category Wise
The seats for admission to the Bachelor’s degree courses at the university are distributed over various categories. These
categories are discussed in Section 31. The details of the distribution of seats are available in the Seats Allocation Chart
in Section 30.
The eligible applicants for each category are grouped separately. Then on the basis of the weighted percentage of
marks obtained in the relevant examinations, comparative merit of the applicants comprising the group is prepared.
The applicants belonging to a category thus compete for admission amongst themselves for the seats allocated to it.
32.8. Transfer on the Basis of Given Preferences and Merit
In case a seat in any Discipline/ Category of higher preference given by a candidate falls vacant and he is eligible for
transfer to that Discipline/Category on the basis of his merit, he shall be automatically transferred to that Discipline/
Category. He will have no right to retain his admission in the previous Discipline/Category because the seat vacated by
him shall be simultaneously allotted to the next eligible candidate on merit.
32.9. Variation in Seats
The university authorities may exercise their right at any time to increase or decrease the number of seats allocated to
any category and there shall be no appeal against such a decision.
32.10. TYPICAL EXAMPLES FOR THE CALCULATION OF WEIGHTED PERCENTAGE FOR ADMISSION
CASE 1:
Applicants having HSSC (FSc) or Equivalent as the highest qualification
Formula
(70×((HSSC marks obtained + NCC +HIFZ-E-QURAN)/HSSC total marks))+ (30×Entry Test marks obtained/Entry Test total marks))
Example
An applicant obtained 848/1100 in HSSC (having passed the HSSC examination as a whole) and 300/400 in Entry Test. He has
obtained NCC Certificate as well.
% Admission Marks
(70×((848+20)/1100))+(30×(300/400))
= 77.736 %
CASE 2:
Applicants having BSc or BASc as the highest qualification
Formula
(35×(HSSC marks obtained/HSSC total marks))+ ((35×BSc marks obtained +NCC+ HIFZ-E-QURAN)/BSc total marks))+(30×(Entry
Test marks obtained/Entry Test total marks))
Example
An applicant obtained 820/1100 marks in HSSC, 624/800 marks BSc (Passed all of them as a whole) and 360/400 marks in Entry
Test, having also NCC certificate:
% Admission Marks
(35×(820/1100))+(35×((624+20)/800))+(30×(360/400))
= 81.265%
ADMISSION PROCEDURES
CASE 3:
Applicants having Diploma of Associate Engineer as the highest qualification
Formula
(70×((Diploma marks obtained + NCC+HIFZ-E-QURAN)/Diploma total marks))+ (30×Entry Test marks obtained/Entry Test total
marks))
Example
An applicant 2570/3100 in Diploma and 240/400 in Entry Test. He has obtained NCC Certificate as well.
% Admission Marks
(70×((2570+20)/3100))+ (30×(240/400)) = 76.483 %