Version 001 â HW18 â gavrin â (25111) 1 This print ... - Web Physics
Version 001 â HW18 â gavrin â (25111) 1 This print ... - Web Physics
Version 001 â HW18 â gavrin â (25111) 1 This print ... - Web Physics
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<strong>Version</strong> <strong>001</strong> – <strong>HW18</strong> – <strong>gavrin</strong> – (<strong>25111</strong>) 1<br />
<strong>This</strong> <strong>print</strong>-out should have 12 questions.<br />
Multiple-choice questions may continue on<br />
the next column or page – find all choices<br />
before answering.<br />
Long and Skinny<br />
<strong>001</strong> (part 1 of 2) 10.0 points<br />
Assumethatthelengthofthesolenoidismuch<br />
larger than the solenoid’s radius and that the<br />
core of the solenoid is air.<br />
Calculate the inductance of a uniformly<br />
wound solenoid having 230 turns if the length<br />
ofthesolenoid is37 cm and itscross-sectional<br />
area is 4 cm 2 .<br />
Correct answer:<br />
mH.<br />
002 (part 2 of 2) 10.0 points<br />
Calculate the self-induced emf in the solenoid<br />
described in the first part if the current<br />
through it is decreasing at the rate of 49 A/s.<br />
Correct answer:<br />
mV.<br />
Inductance of a Solenoid<br />
003 (part 1 of 2) 10.0 points<br />
A solenoid has 104 turns of wire uniformly<br />
wrapped around an air-filled core, which has<br />
a diameter of 11 mm and a length of 4.2 cm.<br />
The permeability of free space is<br />
1.25664×10 −6 N/A 2 .<br />
Calculate the self-inductance of the<br />
solenoid.<br />
Correct answer: 3.07541×10 −5 H.<br />
004 (part 2 of 2) 10.0 points<br />
The core is replaced with a soft iron rod that<br />
has the same dimensions, but a magnetic permeability<br />
of 800µ 0 .<br />
What is the new inductance?<br />
Correct answer: 0.0246033 H.<br />
Inductor in a Circuit 02<br />
005 10.0 points<br />
An inductor that has a resistance of 10 kΩ is<br />
connected to an ideal battery of 128 V. 3 ms<br />
seconds after the switch is thrown the current<br />
in the circuit is 9.472 mA.<br />
Calculate the inductance.<br />
Correct answer: 22.2705 H.<br />
Simple LR Circuit<br />
006 10.0 points<br />
At times prior to t = 0, the switch is open.<br />
The switch is closed at t = 0.<br />
4 kΩ<br />
S<br />
I<br />
12 mH<br />
240 V<br />
When I = 11 mA, what is the potential<br />
difference across the inductor?<br />
Correct answer: 196 V.<br />
Increase and Decay of Current 01<br />
007 (part 1 of 3) 10.0 points<br />
An inductor and a resistor are connected<br />
with a double pole switch to a battery as<br />
shown in the figure.<br />
The switch has been in position b for a long<br />
period of time.<br />
7.65 Ω<br />
9.5 V<br />
137 mH<br />
S b<br />
If the switch is thrown from position b<br />
to position a (connecting the battery), how<br />
much time elapses before the current reaches<br />
95 mA?<br />
Correct answer: 1.42524 ms.<br />
008 (part 2 of 3) 10.0 points<br />
Whatisthemaximumcurrent intheinductor<br />
a long time after the switch is in position a?<br />
a
<strong>Version</strong> <strong>001</strong> – <strong>HW18</strong> – <strong>gavrin</strong> – (<strong>25111</strong>) 2<br />
Correct answer: 1.24183 A.<br />
009 (part 3 of 3) 10.0 points<br />
The switch has brushes within it so that the<br />
switch can be thrown from a to b without<br />
internalsparking. Nowtheswitchissmoothly<br />
thrown from a to b, shorting the inductor and<br />
resistor.<br />
How much time elapses before the current<br />
falls to 141 mA?<br />
Correct answer: 38.9614 ms.<br />
Energy Stored in an Inductor<br />
010 10.0 points<br />
In an RL series circuit, an inductor of 3.03 H<br />
andaresistorof8Ωareconnected toa28.4V<br />
battery. The switch of the circuit is initially<br />
open. Next close the switch and wait for a<br />
long time. Eventually the current reaches its<br />
equilibrium value.<br />
At this time, what is the corresponding<br />
energy stored in the inductor?<br />
Correct answer: 19.0928 J.<br />
Time Constant and Current<br />
011 (part 1 of 2) 10.0 points<br />
The switch in the figure is closed at t = 0.<br />
ε<br />
L<br />
R<br />
Find the time constant of the circuit if L =<br />
35.2 mH, E = 9.83 V, R = 4.78 Ω.<br />
Correct answer: 7.36402 ms.<br />
012 (part 2 of 2) 10.0 points<br />
Calculate the current in the circuit at t =<br />
2.13 ms.<br />
Correct answer: 0.516529 A.<br />
S