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Version 001 – HW18 – gavrin – (25111) 1 This print ... - Web Physics

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<strong>Version</strong> <strong>001</strong> – <strong>HW18</strong> – <strong>gavrin</strong> – (<strong>25111</strong>) 1<br />

<strong>This</strong> <strong>print</strong>-out should have 12 questions.<br />

Multiple-choice questions may continue on<br />

the next column or page – find all choices<br />

before answering.<br />

Long and Skinny<br />

<strong>001</strong> (part 1 of 2) 10.0 points<br />

Assumethatthelengthofthesolenoidismuch<br />

larger than the solenoid’s radius and that the<br />

core of the solenoid is air.<br />

Calculate the inductance of a uniformly<br />

wound solenoid having 230 turns if the length<br />

ofthesolenoid is37 cm and itscross-sectional<br />

area is 4 cm 2 .<br />

Correct answer:<br />

mH.<br />

002 (part 2 of 2) 10.0 points<br />

Calculate the self-induced emf in the solenoid<br />

described in the first part if the current<br />

through it is decreasing at the rate of 49 A/s.<br />

Correct answer:<br />

mV.<br />

Inductance of a Solenoid<br />

003 (part 1 of 2) 10.0 points<br />

A solenoid has 104 turns of wire uniformly<br />

wrapped around an air-filled core, which has<br />

a diameter of 11 mm and a length of 4.2 cm.<br />

The permeability of free space is<br />

1.25664×10 −6 N/A 2 .<br />

Calculate the self-inductance of the<br />

solenoid.<br />

Correct answer: 3.07541×10 −5 H.<br />

004 (part 2 of 2) 10.0 points<br />

The core is replaced with a soft iron rod that<br />

has the same dimensions, but a magnetic permeability<br />

of 800µ 0 .<br />

What is the new inductance?<br />

Correct answer: 0.0246033 H.<br />

Inductor in a Circuit 02<br />

005 10.0 points<br />

An inductor that has a resistance of 10 kΩ is<br />

connected to an ideal battery of 128 V. 3 ms<br />

seconds after the switch is thrown the current<br />

in the circuit is 9.472 mA.<br />

Calculate the inductance.<br />

Correct answer: 22.2705 H.<br />

Simple LR Circuit<br />

006 10.0 points<br />

At times prior to t = 0, the switch is open.<br />

The switch is closed at t = 0.<br />

4 kΩ<br />

S<br />

I<br />

12 mH<br />

240 V<br />

When I = 11 mA, what is the potential<br />

difference across the inductor?<br />

Correct answer: 196 V.<br />

Increase and Decay of Current 01<br />

007 (part 1 of 3) 10.0 points<br />

An inductor and a resistor are connected<br />

with a double pole switch to a battery as<br />

shown in the figure.<br />

The switch has been in position b for a long<br />

period of time.<br />

7.65 Ω<br />

9.5 V<br />

137 mH<br />

S b<br />

If the switch is thrown from position b<br />

to position a (connecting the battery), how<br />

much time elapses before the current reaches<br />

95 mA?<br />

Correct answer: 1.42524 ms.<br />

008 (part 2 of 3) 10.0 points<br />

Whatisthemaximumcurrent intheinductor<br />

a long time after the switch is in position a?<br />

a


<strong>Version</strong> <strong>001</strong> – <strong>HW18</strong> – <strong>gavrin</strong> – (<strong>25111</strong>) 2<br />

Correct answer: 1.24183 A.<br />

009 (part 3 of 3) 10.0 points<br />

The switch has brushes within it so that the<br />

switch can be thrown from a to b without<br />

internalsparking. Nowtheswitchissmoothly<br />

thrown from a to b, shorting the inductor and<br />

resistor.<br />

How much time elapses before the current<br />

falls to 141 mA?<br />

Correct answer: 38.9614 ms.<br />

Energy Stored in an Inductor<br />

010 10.0 points<br />

In an RL series circuit, an inductor of 3.03 H<br />

andaresistorof8Ωareconnected toa28.4V<br />

battery. The switch of the circuit is initially<br />

open. Next close the switch and wait for a<br />

long time. Eventually the current reaches its<br />

equilibrium value.<br />

At this time, what is the corresponding<br />

energy stored in the inductor?<br />

Correct answer: 19.0928 J.<br />

Time Constant and Current<br />

011 (part 1 of 2) 10.0 points<br />

The switch in the figure is closed at t = 0.<br />

ε<br />

L<br />

R<br />

Find the time constant of the circuit if L =<br />

35.2 mH, E = 9.83 V, R = 4.78 Ω.<br />

Correct answer: 7.36402 ms.<br />

012 (part 2 of 2) 10.0 points<br />

Calculate the current in the circuit at t =<br />

2.13 ms.<br />

Correct answer: 0.516529 A.<br />

S

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