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Lecture notes for Introduction to Representation Theory

Lecture notes for Introduction to Representation Theory

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Proposition 5.31. Let Q be a quiver and V a representation of Q.<br />

1. Let i Q be a sink and let V be surjective at i. Then<br />

d(F i + V ) = s i (d(V )).<br />

2. Let i Q be a source and let V be injective at i. Then<br />

d(F i − V ) = s i (d(V )).<br />

Proof. We only prove the first statement, the second one follows similarly. Let i Q be a sink and<br />

let<br />

: V j ⊃ V i<br />

be surjective. Let K = ker . Then<br />

There<strong>for</strong>e we get<br />

j⊥i<br />

dim K = dim V j − dim V i .<br />

j⊥i<br />

⎩<br />

d(F + V ) − d(V ) = dim V j − 2 dim V i = −B (d(V ), ϕ i )<br />

i<br />

i<br />

j⊥i<br />

and<br />

This implies<br />

⎩<br />

d(Fi + V ) − d(V ) j<br />

= 0, j ⇒ = i.<br />

d(F i + V ) − d(V ) = −B (d(V ), ϕ i ) ϕ i<br />

⊆ d(F + V ) = d(V ) − B (d(V ), ϕ i ) ϕ i = s i (d(V )) .<br />

i<br />

5.7 Coxeter elements<br />

Definition 5.32. Let Q be a quiver and let be the underlying graph. Fix any labeling 1, . . . , n<br />

of the vertices of . Then the Coxeter element c of Q corresponding <strong>to</strong> this labeling is defined as<br />

Lemma 5.33. Let<br />

c = s 1 s 2 . . . s n .<br />

α = k i ϕ i<br />

with k i ⊂ 0 <strong>for</strong> all i but not all k i = 0. Then there is N N, such that<br />

has at least one strictly negative coefficient.<br />

i<br />

N<br />

α c<br />

93

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