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Lecture notes for Introduction to Representation Theory

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of x := ⎛ x j<br />

j<br />

in the polynomial<br />

<br />

Hm (x) im .<br />

⇒<br />

Lemma 4.42. c is proportional <strong>to</strong> an idempotent. Namely, c <br />

2 n!<br />

= dim<br />

V <br />

c .<br />

Proof. Lemma 4.40 implies that c 2<br />

is proportional <strong>to</strong> c . Also, it is easy <strong>to</strong> see that the trace of<br />

c in the regular representation is n! (as the coefficient of the identity element in c is 1). This<br />

implies the statement.<br />

Lemma 4.43. Let A be an algebra and e be an idempotent in A. Then <strong>for</strong> any left A-module M,<br />

one has Hom A (Ae, M) ∪ = eM (namely, x eM corresponds <strong>to</strong> f x : Ae ⊃ M given by f x (a) = ax,<br />

a Ae).<br />

Proof. Note that 1 − e is also an idempotent in A. Thus the statement immediately follows from<br />

the fact that Hom A (A, M) ∪ = M and the decomposition A = Ae A(1 − e).<br />

Now we are ready <strong>to</strong> prove Theorem 4.36. Let ∂ ⊂ µ. Then by Lemmas 4.42, 4.43<br />

Hom Sn (V , V µ ) = Hom Sn (C[S n ]c , C[S n ]c µ ) = c C[S n ]c µ .<br />

The latter space is zero <strong>for</strong> ∂ > µ by Lemma 4.41, and 1-dimensional if ∂ = µ by Lemmas 4.40<br />

and 4.42. There<strong>for</strong>e, V are irreducible, and V is not isomorphic <strong>to</strong> V µ if ∂ = µ. Since the number<br />

of partitions equals the number of conjugacy classes in S n , the representations V exhaust all the<br />

irreducible representations of S n . The theorem is proved.<br />

4.14 Induced representations <strong>for</strong> S n<br />

Denote by U the representation Ind Sn C. It is easy <strong>to</strong> see that U can be alternatively defined as<br />

P <br />

U = C[S n ]a .<br />

Proposition 4.44. Hom(U , V µ ) = 0 <strong>for</strong> µ < ∂, and dim Hom(U , V ) = 1. Thus, U =<br />

µ∧ K µ V µ , where K µ are nonnegative integers and K = 1.<br />

Definition 4.45. The integers K µ are called the Kostka numbers.<br />

Proof. By Lemmas 4.42 and 4.43,<br />

Hom(U , V µ ) = Hom(C[S n ]a , C[S n ]a µ b µ ) = a C[S n ]a µ b µ ,<br />

and the result follows from Lemmas 4.40 and 4.41.<br />

Now let us compute the character of U . Let C i be the conjugacy class in S n having i l cycles<br />

of length l <strong>for</strong> all l ⊂ 1 (here i is a shorthand notation <strong>for</strong> (i 1 , ..., i l , ...)). Also let x 1 , ..., x N be<br />

variables, and let<br />

m<br />

H m (x) = x i<br />

i<br />

be the power sum polynomials.<br />

Theorem 4.46. Let N ⊂ p (where p is the number of parts of ∂). Then ν U (C i ) is the coefficient 6<br />

6<br />

If j > p, we define j <strong>to</strong> be zero.<br />

m∧1<br />

60

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