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Lecture notes for Introduction to Representation Theory

Lecture notes for Introduction to Representation Theory

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Thus <strong>for</strong> g G we have<br />

ν V (g 2 ) = ν S 2 V (g) − ν 2 V (g)<br />

There<strong>for</strong>e,<br />

⎞<br />

⎟ 1, if V is of real type<br />

| G| −1 ν 2 V ) G<br />

V ( g 2 ) = ν S 2 V (P )−ν √ 2 V (P ) = dim(S 2 V ) G −dim(√ = −1, if V is of quaternionic type<br />

⎠<br />

gG<br />

0, if V is of complex type<br />

Finally, the number of involutions in G equals<br />

1 <br />

<br />

dim V ν V ( g 2 ) = dim V − dim V.<br />

|G|<br />

V<br />

gG real V quat V<br />

Corollary 4.5. Assume that all representations of a finite group G are defined over real numbers<br />

(i.e., all complex representations of G are obtained by complexifying real representations). Then<br />

the sum of dimensions of irreducible representations of G equals the number of involutions in G.<br />

Exercise. Show that any nontrivial finite group of odd order has an irreducible representation<br />

which is not defined over R (i.e., not realizable by real matrices).<br />

4.2 Frobenius determinant<br />

Enumerate the elements of a finite group G as follows: g 1 , g 2 , . . . , g n . Introduce n variables indexed<br />

with the elements of G :<br />

x g1 , x g2 , . . . , x gn .<br />

Definition 4.6. Consider the matrix X G with entries a ij = x gi g j<br />

. The determinant of X G is some<br />

polynomial of degree n of x g1 , x g2 , . . . , x gn that is called the Frobenius determinant.<br />

The following theorem, discovered by Dedekind and proved by Frobenius, became the starting<br />

point <strong>for</strong> creation of representation theory (see [Cu]).<br />

Theorem 4.7.<br />

<br />

r<br />

P j (x) deg P j<br />

det X G =<br />

j=1<br />

<strong>for</strong> some pairwise non-proportional irreducible polynomials P j (x), where r is the number of conjugacy<br />

classes of G.<br />

We will need the following simple lemma.<br />

Lemma 4.8. Let Y be an n × n matrix with entries y ij . Then det Y is an irreducible polynomial<br />

of {y ij }.<br />

n<br />

Proof. Let Y = t·<br />

Id+ ⎨ i=1 x iE i,i+1 , where i+1 is computed modulo n, and E i,j are the elementary<br />

matrices. Then det(Y ) = t n − (−1) n x 1 ...x n , which is obviously irreducible. Hence det(Y ) is<br />

irreducible (since fac<strong>to</strong>rs of a homogeneous polynomial are homogeneous).<br />

Now we are ready <strong>to</strong> proceed <strong>to</strong> the proof of Theorem 4.7.<br />

48

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