FK 40 - Tri-Canada

FK 40 - Tri-Canada FK 40 - Tri-Canada

03.11.2012 Views

Positive displacement pumps Case 1: viscosity η ∪ 1 mPa s Step 3: Calculate t he power N [kW] required f or t he pump drive. p = pressure [bar] V = viscosity factor n = speed [1/min], stated in the diagram C = flow rate/revolution [l/rev.] Example:

Example: Q = 3000 l/h H = 120 m ∪ p = 12 bar η = 10 mPa s Step 1: speed correction stated in the diagram: p = 3.8 bar. Def ine now t he speed required f or t he correct ed pressure. Positive displacement pumps Case 2: viscous product η up to 200 mPa s

Example:<br />

Q = 3000 l/h<br />

H = 120 m ∪ p = 12 bar<br />

η = 10 mPa s<br />

Step 1:<br />

speed correction<br />

stated in the diagram: p = 3.8 bar.<br />

Def ine now t he speed required f or t he correct ed pressure.<br />

Positive<br />

displacement<br />

pumps<br />

Case 2:<br />

viscous product<br />

η up to 200 mPa s

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