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130 CWAPTER 4 Newton's Laws of Motion<br />
Key Terms<br />
dynamich. If17<br />
Newton's lawa ol motion, 107<br />
classical (Newlnnian) ~nwhanics, 107<br />
force. 108<br />
contact force, 108<br />
r~ortnal force, 108<br />
f~,ic.tion force, 108<br />
tctlsiot~ €orce, 108<br />
long-rancz rurces, 108<br />
weight. I08<br />
superposition nf forces, IUY<br />
net force, IIO<br />
Newton's first law oCmc)tion, Ill<br />
inerria. 112<br />
eyuilibrii~t~i, 112<br />
inertial frame of reference, 113<br />
tIMS5, lib<br />
kilogratl~. 116<br />
~IP.W[OII, I16<br />
Newtuu'r s.e~.ond Ii~rv of molicln, 117<br />
Newton's third law of motion, 123<br />
action-reactiot~ pair. 123<br />
tension, 126<br />
free-body diagram, 127<br />
Answer to Chapter Opening Question 7<br />
Newton's lhird law wlla u> that the seated child (who we'll call<br />
Ryder) pushes a1 the btantling cllild (who we'll call Slan) just as<br />
hard as Stan pushrh on Kydzr. but In the opposite direction. This is<br />
tme whether Rydrr pu\he\ I)n Sun "actively" (for instance, if<br />
Ry&r pushed his hand again.;[ Stan's) w "passively" (if Ryder's<br />
back does the puching, ~LS in the photograph that opens the chaptco.<br />
The force niagniludes would he gr-cater in the "active" case<br />
than in the "passive" case, hul either way Ryder's push otl St,m is<br />
iuat as strot12 as Stan's puqh on Kyder.<br />
Answers to Test Your<br />
Understanding Questions<br />
4.1 Answcr: (iv) The gr~vitatiunill force on the crate poinrs<br />
straight downward. In Fig. 4.6 thc x-axis points up and to the<br />
right, and the y-axih pr~ints up and to the left. Hence the gravila<br />
tianal force has both 21) ~-cornponcqit and a y-component, anci<br />
both arc negative.<br />
4.2 Answer: (i), (ii), a ~ (ir) ~ d 111 (i). (~i!. ar~d (iv) the body is out<br />
accelerating, so the net force on Ihr huJy ih zero. [In (iv), the box<br />
rema~ns stationary as seen in the iner~ial rcfircncc frame of the<br />
ground as the truck actcceleraies forward, likc the skater in<br />
Fig. 4. I la.] In (iii), the hawk is moving in a ~,ircle: hcncc it is<br />
accelwati~ip and ri tlor in equilibrium.<br />
4.3 Answer: (iii), (i) and (iv) (tie), (ii) The accelrra~ion is zqir~l to<br />
the net ftirlrcc divided by the mass. Hence the ~nagn~~udt of thr<br />
accrleratiilrl UI each situation is<br />
0) Q = (2.0 ~)](2.0 kg) = 1.0 m/s2:<br />
(ii) u = (x.0 N j /(2.0 N ) = 4.0 rnls2:<br />
(iil) a = (2.0 N)I{XII<br />
kg) = 0.25 1111s-.<br />
(ib) n = (8.0 N ) l(8.0 kg ) = 1.0 1111s'.<br />
4.4 It would Lake twice the effort tot thc iiSU'OWdUt to walk WUUII~<br />
because her weight un the planrt wculrl bc twice as much as on the<br />
earth. Bul ir would he just a< easy 11, catct~ a ball moving hosizontally.<br />
The ball's ?nun is the Fame ah nn carth, so thc horizontd<br />
force the astronaut woulcl have to exert tc~ bring it tc) a stop he.. tu<br />
give it the same acceleration) would also he lhe same as on earth<br />
4.5 Uq' Newton's third law, the two forces have equal magnitudes<br />
Because the car has much greater mass than (he mohquito. it under-<br />
FDCS only a tiny. itnpercepiible acceleration in rebptmsr to the<br />
tnrcc of the uupact By contrast, the mosquito, with 11s mlnuccult<br />
rndss. undergoes a catastrophically large acceleration.<br />
4.6 Answer: (i\) Thc buoyancy force is an uptpwurrl force that the<br />
wntir exznc on thc nrmrmnaPP: By Newton's third law, the other half<br />
of the ;c~ioii-rza~tiun p~irs a dowawnrd fo~cc that the slt.immer<br />
rxt'rth on the wat~r and has the same magnitildr: ns the buoyancy<br />
force. ll's (rut: that tbc wcight of the sw~nutlet is aIso downward<br />
and has (he sanic magnitude ss tl~c b~oy~ltlcy force: however, the<br />
weight acls un the 5amc borlv (TIIF bwillunet) as the buoyancy<br />
force, and so Ihe5e force'; aren't an act~nn-rfiic'tio~i pair.<br />
<strong>PROBLEMS</strong><br />
,.-.-,.-- -.-.----.--.-- -- ," ------a-A ...<br />
For ir~structor-asstgrled hnrnwvurk, gu ro www.rnasteringphysics.com<br />
--- --,--.--..--.--.,-.,-..--.-..-.<br />
Discussion Questions<br />
m.1. Can :I body he in equ~ljbriu~li when 0111 one force acts on it?<br />
Explain.<br />
Q4.2. A hall thrown straighr up hns zert? velocity at its highcst<br />
point. Is lhe ball in equilibrium at thiq point? Why or why nut'!<br />
44.3. A helium balloon ROYCIS In mirl:~ir, ne11h.e:- ascending nor<br />
descending. Is it in equilibrium? What foxes acl on iit?<br />
44.7. WRrn a r.31 \tops suii~lcnly, the passengers tend to make forward<br />
rela11te t ~ tlxit- ) seat>. Why'! When a car inakes a sharp turn,<br />
the passengers rend ro slid< to une side of thc car. Why?<br />
44.8. Same people say that thc "force of inertia" (or -'force of<br />
momenlum") throws the passevgers forward whcn n car brakes<br />
sharply. Whai is wrong with this explanation'!<br />
44.9. 4 passenger in 3 moving bus 1l:irh Ilo WIII~~WL<br />
notizcs that a<br />
ball ttl~t has been at xsl in the aisle xuddenl? stam ttj tnove toward<br />
the rwr of the bus. Think of two dilTerenl p>hsthle ekplwations,<br />
iilid devise a way to decide which is crlrrecl.<br />
44.10. Suppose you chose the fundanjental SI units 10 he rorcrce,<br />
le11gt11. atid time instead of mass, length, hnd time. What would he<br />
Q4.4. When you fly in ail airplane at night in smooth air. there i<<br />
no sensation of mtrlicrn, ecen though the plane rnay be rnovin~ at<br />
800 hnlh ( 50(1 n11/ h ) . Why is this:'<br />
Q4.5. If the twr end5 r)f a rope in equilibrium are pulled ~.iih<br />
forces of elpal magnltucle and opposite direction: why is rhr torah the ullits of mass iri terms of lhose r~nda~nental ~mits?<br />
tcnsion in lhe rup no1 /~I-O.!<br />
Q4.11. Some of the ancient Greeks thought that the "nat~~ral stale"<br />
Q4.6. You tie :I bn~k II? the end uf a rope and whirl rht brick uf an object was to be at rest. so objects would seek their natural<br />
muund you in a horjzonral iir~le. Describc thc path ol the brick stale by cuining tu rclt lt left alotle. Explain why this view can<br />
after you suddenly let go of the ]-ope.<br />
actwilly heem qulle plau\ihlc iti t 1 eve~yday ~ world.
Exercises 1 31<br />
44.12. Why is Lhe earth o~ily approximately an inertial reference<br />
frame?<br />
04.13. Does Newton's second law hold rnle for an observer in a<br />
van as it speeds up, slows down, or rounds a corner? Explain.<br />
44.14. Sorne students refer to the quantity naz as "the force of acceleration."<br />
Is it correct to refer to this quantity as a force? If so, what<br />
exerts this force? If not. what is n better description of this quantity9<br />
44.15. The acceleration of a falling body is measured in an elevator<br />
traveling upward at a constant speed of 9.8 m/s. What result is<br />
obtained?<br />
Q4.16. Yuu can play catch w~tb a suttbdl in a bus moving wrth<br />
cunstant spccd un a straight road. just as though thc bus wcrc at<br />
rest. Is this still po~siblc whca thc bus is mnking 21 turn at ct>nstant<br />
speed 011 a level ruad'! Why or why notr!<br />
44.17. Students sumetimes say that the tcjrce uf gravrty
132 CHAPTER 4 Newton s Laws of Motion<br />
4.3. A warehou>c wurker pushes a crate alot~g the floor, as shown<br />
in El:. 4.3 I . with a for a ptihul~ ulth<br />
mass 60 kg who is resting on the edge 01' 3 h\r imminp pool, whar<br />
hori~c~ntal ilccclcration is produced9<br />
4.8. What rriagnit~lrle OF net fforce is rcquned tcr pve a 135-kg<br />
refrigerator an accclcration of magnitude 1.40 mls"~<br />
4.9. A box rests on a frozen pond, n,l~ich scrvcs ;is a frictionless<br />
horizontal surrace. If a fishcrmm applies a horizontal force ivilh<br />
niagn~rudc 413.0 N to the box and p~nduces an accelcrahon of magnitude<br />
3.110 mls', what 15 rhc mlus of the box?<br />
4.10. .4 dockwtrrker iipplic\ a cotisant horizontal force or 80.0 N<br />
ro a block (rf ice trn a smrwth Iltwizontal floor. The frictionul force<br />
is neplieiblc. The hlwk 5t~t-t~ from rest and moves 11.0 m in<br />
5 00 s. (a) What is the mass of the block of ice? (b) If the worker<br />
4.18. A bowling ball weighs 71.2 N (16.0 Ib). The bowler :~pplieh a<br />
hurizont~~ force of 160 N (36.0 Ib) to the ball. What is the magnitude<br />
of the hori7c)ntal accclcration of the ball?<br />
4.19. A1 the surface of Jupiter's moon Icr, the acceleration due to<br />
tty is g = 1.81 in/s2. A watermelon weighs 44.0 N at the surf;~~?<br />
or' ihe earth. (a) What js the watcrrnelon's mass on the earth's<br />
surr'acr" (b) Whal are its lnass and wcight on the surface of Io?<br />
4.20. An asironaul's pack weighs 17.5 N whcil she is on earth but<br />
only 3.24 N when she is :it the surface of an asteroid. (a) What is<br />
tile acceleration due to graviiy on this asteroid? (h) What is hc<br />
t11;lsu of the pack on the asteroid'!<br />
(R) What is the reaction to eaih force; ih~t<br />
by which body is the reaction exertzcl?<br />
4.24. Thc upward ~larrnal torce exerted bj the floor is h20 N un an<br />
elevahr passenger who weigh> 650 N. Wh21t are the reaction<br />
tnrcc~ to these two forces? Is rlw p,~s~enger :~ccelerating? If su,<br />
what arc the 111agnitude and dirwrior~ of thz acceleration?<br />
4.25. A >tudcnt wth mass 45 kg jur~ps off a high diving huard.<br />
hing 6.0 /: 10" !q fc~r thc tn:~ss of the earth, what is the acceleration<br />
t)f the earlh toward hst 15: shc ~ccrlerates toward the earth<br />
wilh an accrleration ol q.8 III/~':' Ass~itlle that the net force on the<br />
enrlh is the f~~rcr uf gravity shc cxct-ts otl it.<br />
Sectron 4.6 Free-Body Diagrams<br />
4.26. hn athlete throws a ball of 11m.5 ~ I I dmctl upaard, and II<br />
feels no apprzciahlz air reslstancc. Dr~a n tter-body diagram of<br />
~hjs ball wh~lr 11 i< lrrz ot the athlctc's hm~i atid (a) moving<br />
upward. Ib) ilt itc highr\~ point; (c) movlng doivnw:ird. (d) Repeat<br />
parts (a), (b). nnd (c) if the athlete throws rht. h~ll at .J ho" li~igls<br />
abuvc thc horizo~lral instead of rlllrctl) ilpwitrd.<br />
4.27. Two cratcs, ,-I snd B. it st rest side by side 011 ,I hi'rictionlzrr<br />
h- the earth equal 'ind<br />
opposite to the force exerted on the earth 1y thr book? (k) Is the<br />
force exerted on the hook by yuur hand qua1 snd opposirt ro the<br />
force exerted on your hand by the buok'l Finally, suppose you<br />
constwt s ~ed by a tow rope that is pwallcl to the gmund. The<br />
snatch your hand away while the book is moving upu'ard. (1) Horv<br />
guund sl.Ur 3bo1 c thc hnrimany<br />
forces then act on the btak? (m) Is thc book in equilibrium?<br />
zntal, and you ran ignore friction. (a) Draw a clciuly lal~clcd frcc-<br />
4.23. A bottle is given a push alung a tliblctop and slides off the<br />
hdy diagriim fur the skier. (h) Calculate the tensiun In Ihe tna rope<br />
edge of the table. Do nor ignurc air resibtsncc. (a) What forces are<br />
4.33. A truck is pulling u car un a hurixuntal hrghwuy using a hariexerted<br />
on the bottle while it is call in^ from the table to thc floor?<br />
zontal rope. The car is in neutral gem, so we can mumt thal Ihrrr.<br />
is, on which budy and<br />
is no appreciable friction between its tires and the high\\,ay. .As thr<br />
truck is accelerating to highway speeds, draw a free-body dinpam<br />
of !a) the car and (b) the truck. (c) What force accelemlrs this systern<br />
forward? Explain how this force originates.<br />
Problems<br />
4.34. A 22 siflc bullct, travclmg at 350 xnls, strikcs a luge net,<br />
which it peiietrdtes tu a depth of 0.130 m. The mfis c)f the bullet i\<br />
1.80 g. Assume a constant retarding furce. (a) Ho~v much tline 1s<br />
required fc)s the bullet to stop'! (b) What forcc, in ilcu7tuns. does the<br />
tree exert un the bulletr!<br />
4.35. 'Tiw horses pull hc~i~onntally<br />
lopes attached to a wimp<br />
-><br />
The iwo forces P, and k: that they apply tu the stump are such that<br />
the net (resultant) force 3 h? a magnitude equal to that of z1 and<br />
makes an angle of 90" aith c,. Let F, = t3W N &mJ H = h300 N<br />
also. Find the magnih~de of F, and its direction r relarive to F,)
134 C HAP T E R 4 Nebvtcln's Ldws of Motion<br />
4.36. You hht2 ~U\I Isndeil on Pktnct X. You take out a 100-g ball. hare u mass of 55.0 kg, a~ld air resistatice rwrts a ttrlill upwarrl<br />
release ~t fro111 rest Cram ;1 height OF 10.0 m, and n1easurt that it rcrrce c~f h20 N on hcr and her parachute. (a) \I'hnt is thr &eight tjt<br />
takes 2.2 s ro reach ihe ~ ~ound. You c~~i ignnrc any force on the the paraciiuiist'! (b) Draw a free-body diagram fur ihr p;lrachuti.;i<br />
bdl frij~n the amlosphere of the planet. Ho\r much duel thc 100-p<br />
b;tlI weigh on the surface of Plane[ X?<br />
(see Section 4.6). Use that diagram to calculate ihe nrt force on the<br />
parxhutisl. Is the net force upward or downwx-d7 tc) What 1s the<br />
4.JT TWO adults and n child want Figure 4-36 ~ ~ 4.37. ~ t ,<br />
L~czlen~tion<br />
\ ~ ~<br />
(magnitude ar~d~rectionj of the paraslx~t~sl?<br />
to push a wheeled cart in the<br />
4.43. Tcvu crates, one with mass 4.00 kg and the otbttr w~ih mars<br />
rl11,cciion nrarked x in Fig. 4.36.<br />
6.09 kg, sit on the frictionless surface uf a frozen pond, connecwd<br />
b@f<br />
The two ;~dults push with-hori-<br />
by a light rope (Fig. 4.38). A wuinan wcasing golf shoes (so she<br />
,ont:il forces ?, and F2 as<br />
cml get traction on the ice) pulls horizontally nn the 6.00-kg crate<br />
sh~)wn in the figure. (a) Find the<br />
with a force F that gives the crate an accceleratiuii uf 2-50 mls2.<br />
'<br />
rt~~~giilude and direction of the<br />
(ii) What 1s the acceleration of the 4.00-kg ct-ale'! (b) Draw a frccsnl~~llc.~t<br />
force that the child<br />
body diiigran~ for the 4.00-kg crate. Use that diagram aiid Ncw-<br />
\ha~llcl cxefl. Yuu can ignore the<br />
ton's second law tcr firid the tensicrn Tin lhc n)pe that connects thc<br />
cffer.!.; or friction. (b) If thc<br />
two cratcs. (c) Dm\\- a free-body diagram I;)r lhe 6.00-kg crate.<br />
ch~ld txeris ihe minimum forcc<br />
What is thc direcdon of the net force on [he b 00-kg crate'? Which<br />
found in part (a). the cart<br />
ix larger in magnitudc. fwrr T or force b"l id) Use part (c) and<br />
accelerates at 2.0 mla' in the<br />
+x-direction. I+'hat IS the weight tlf the iiut'.'<br />
4.38. An oil tankrl.'~ rnginea have hrnbtl down, and the wind is<br />
blowing the tanker s~r.lighl tuward 3 ~ ct' ;kt a constallt speed of<br />
Newton's second law tn c~lcilliiie the t~~agturudt: of the force F.<br />
4.44. An aqlmna~rt is trtherzd by a strong cable to n spacecraft.<br />
The ahtronaut and hcr spaccsujt hve a tod nuas of 105 kg, while<br />
the masx of the cable IS ncpligjble. The Inass of the spacecraft is<br />
1.5 ni/s (Fig. 4.37). Whrn thr tanker IS 5C)U 111 from the reef, the<br />
wind dies down jusi as Ihr: enginerr gets thc cnpines going again.<br />
9.05 x I# kg. The hp;icecr;ift is far from any large astruncrmical<br />
TRc rudder is stuck. 50 the only choice 1% ttj try to accelerate<br />
straight backward awa? from rhe red. The makh of the tankcr ;md<br />
Figure 4.38 Problern 4.43<br />
cargo is 3.h X 10' kg. and the engines produce a nrt horii..ontul<br />
force uf 8.0 X 10% on the tanker. Will Lhe ship hit the rat:' [L it<br />
does, will thc nil be safe? The kuIl can withstand an ilnpact ;it a<br />
sped of 0.2 in/\ or less. You can ignore the recarding for~,e nf ~hc<br />
waler on the ~ulkcr's hull.<br />
Flgure 4.37 Problem 4.38.<br />
hodith, ho *t. cat1 lgnorc thc gravitational forces on it and the<br />
aclrr,n;irlt. We ;11w assume that both the spacecraft and ttw astmnaut<br />
are initially at rcst in an inertial reference frame. The nstronaut<br />
then pulls on the cable \\ith a force of 80.0 N. (n) What force<br />
does the cable exert on the ast~-oneut? (hj Slnce LF = trd, how<br />
can a "mas~less" (nr = 0) cublc exert ;l force'? (2) WLut is the<br />
4.39. -4 Standing Vcrtical Jump. Baskethall playct Darrell aslronaul's acceleratic)nr! (d) What forcc docs the cable ~ W Lon K the<br />
Ciriftith is on record as attuning a standing vert~cal iu111p ot' 1.2 111 spacecraft? (e) Whal is the ;lccelsratil~n c,f the sp~c!c.cir~ft'.'<br />
(4 ft). (Thismeans that he mnwd upward hy I .2 m aftc't. his feet left 4.45. To srudy damage aircraft that cullldc wlth luge birds.<br />
the Row) Grif3ith weighed 890 N (:MI Ih). (a) What is his speed as you design a Lest gun that will accelerutc chickcn-sized objects so<br />
he leaves the floor? (b) If the tilnr nf rhc plirt c ~ the t ii1111p bctbre his that their displacemenl almg the gun barrel 1s givcn by A =<br />
led left thc floor was 0.300 s, wha~ x.a$ his arerJgc. wcclerdtion (9.0 X lo3 rnls2)t2 - (8.0 X l(Y] rn/l;')l3. The ubjcct lcavcs the<br />
(magnitutic and direction) while hr pt~shing agntlst the tloor? end of the barrel ai t = 0.025 s. (a) How lung must hc gun barrel<br />
(c) maw his free-bdy bgram (scr Sr~,tion 4.h). In ktni~ c~f the be? fi) What will be the speed of the objecu as they leave the eiid<br />
forces nn the diagram, wh;it is the net force un h~m? Use Nrkbtc~n's of the barrel? (c) What net force must be exeried on a I 30-kg<br />
laws and the results of part (h) tu s~lculnre the average l'orcz he objcct at (i) t = 0 and (iil I - 0.025 s'?<br />
applied io the ground.<br />
4.40. An arlvertiseirlent chiins that a particular ;~u~olnobile can<br />
"stop on a dime." What nct force would actually he necesxmy tu<br />
stop a 850-kg autoi~lobile t~ avslinp initially at 15.0 ktnlh in a distance<br />
equal to the dran~ete~ ot i dirnc, which is 1.8 cm?<br />
4.41. A 4 8Wkg bucket or wilier i~ accclcrated lipwacd by ;I curd of<br />
negligible mass whose breaking strength is 75.0 N. (a) Draw the<br />
trce-bod>- force d~agrarii Ikr the bucket. In terms of the forces on<br />
your dinglam, whar is the twi [iircc on thc bucket'! (b) Apply Newton'~<br />
sccond law lo t ! hucket ~ and find thc maximurn upward accelwatioii<br />
that can be given to ihc bucket without breaking the cord.<br />
4.42. A pa~acbut~st rzlles on alr I-esixtance (mainly on her pnrachute)<br />
111 decrcasc hcr downward veloci~y. She and her parachute<br />
4.46, A spxczcraft descends vertically near the surrace of Aanet X<br />
,411 upward thrust of 25.0 kt4 from its engines slows it down al a<br />
rntr of 1.20 n~lsl, but it speeds up at a rate of 0.80 m/s2 with an<br />
upru-d 11lrut.t ot 10.0 I;N. (,I) LI each case: what is the direclinn of<br />
the rlccclcratipn of the spac.ecr.~ft? (b) Draw a free-body rliagdm<br />
Tor rhz spa~,tcraft In e ~ct~~~~;c, speeding up or slowiiing down, what<br />
i~ the dilrc~ir>ii ot ihe net fi~rcc a11 thc spacecraft? (c) Apply New-<br />
:on'$ ~;t'c