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Phase Cycling and Gradient Pulses - The James Keeler Group

Phase Cycling and Gradient Pulses - The James Keeler Group

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step<br />

pulse<br />

phase<br />

phase shift experienced<br />

by transfer with ∆p = +1<br />

equivalent<br />

phase<br />

rx. phase to<br />

select ∆p = –3<br />

difference<br />

1 0 0 0 0 0<br />

2 90 –90 270 270 270 – 270 = 0<br />

3 180 –180 180 180 180 – 180 = 0<br />

4 270 –270 90 90 90 – 90 = 0<br />

Here we see quite different behaviour. <strong>The</strong> equivalent phases, that is the phase<br />

shifts experienced by the transfer with ∆p = 1, match exactly the receiver<br />

phases determined for ∆p = –3, thus the phases in the "difference" column are<br />

all zero. We conclude that the four step cycle selects transfers both with ∆p =<br />

–3 <strong>and</strong> +1.<br />

Some more work with tables such as these will reveal that this four step<br />

cycle suppresses contributions from changes in coherence order of –2, –1 <strong>and</strong> 0.<br />

It selects ∆p = –3 <strong>and</strong> 1. It also selects changes in coherence order of 5, 9, 13<br />

<strong>and</strong> so on. This latter sequence is easy to underst<strong>and</strong>. A pathway with ∆p = 1<br />

experiences a phase shift of –90° when the pulse is shifted in phase by 90°; the<br />

equivalent phase is thus 270°. A pathway with ∆p = 5 would experience a<br />

phase shift of –5 × 90° = –450° which corresponds to an equivalent phase of<br />

270°. Thus the phase shifts experienced for ∆p = 1 <strong>and</strong> 5 are identical <strong>and</strong> it is<br />

clear that a cycle which selects one will select the other. <strong>The</strong> same goes for the<br />

series ∆p = 9, 13 ...<br />

<strong>The</strong> extension to negative values of ∆p is also easy to see. A pathway with<br />

∆p = –3 experiences a phase shift of 270° when the pulse is shifted in phase by<br />

90°. A transfer with ∆p = +1 experiences a phase of –90° which corresponds to<br />

an equivalent phase of 270°. Thus both pathways experience the same phase<br />

shifts <strong>and</strong> a cycle which selects one will select the other. <strong>The</strong> pattern is clear,<br />

this four step cycle will select a pathway with ∆p = –3, as it was designed to,<br />

<strong>and</strong> also it will select any pathway with ∆p = –3 + 4n where n = ±1, ±2, ±3 ...<br />

9.5.2 General Rules<br />

<strong>The</strong> discussion in the previous section can be generalised in the following way.<br />

Consider a phase cycle in which the phase of a pulse takes N evenly spaced<br />

steps covering the range 0 to 2π radians. <strong>The</strong> phases, φ k<br />

, are<br />

φ k<br />

= 2πk/N where k = 0, 1, 2 ... (N – 1).<br />

To select a change in coherence order, ∆p, the receiver phase is set to<br />

–∆p × φ k<br />

for each step <strong>and</strong> the resulting signals are summed. This cycle will, in<br />

addition to selecting the specified change in coherence order, also select<br />

pathways with changes in coherence order (∆ p ± nN) where<br />

n = ±1, ±2 ..<br />

<strong>The</strong> way in which phase cycling selects a series of values of ∆p which are<br />

related by a harmonic condition is closely related to the phenomenon of aliasing<br />

in Fourier transformation. Indeed, the whole process of phase cycling can be<br />

9–23

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