Exam in Antenna Theory - Space.irfu.se
Exam in Antenna Theory - Space.irfu.se
Exam in Antenna Theory - Space.irfu.se
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<strong>Exam</strong> <strong>in</strong> <strong>Antenna</strong> <strong>Theory</strong><br />
Time: 18 March 2010, at 8.00–13.00.<br />
Location: Polacksbacken, Skrivsal<br />
You may br<strong>in</strong>g: Laboratory reports, pocket calculator, English dictionary, Råde-Westergren: “Beta”,<br />
Nordl<strong>in</strong>g-Österman: “Physics Handbook”, or comparable handbooks.<br />
Six problems, maximum five po<strong>in</strong>ts each, for a total maximum of 30 po<strong>in</strong>ts.<br />
1. a) If the complex electric field is denoted E(r), f<strong>in</strong>d the correspond<strong>in</strong>g <strong>in</strong>stantaneous (timedependent)<br />
electric field E(r,t).<br />
(1p)<br />
b) The array factor of a N-element uniform array can be written<br />
AF = s<strong>in</strong>( N<br />
2 ψ)<br />
s<strong>in</strong> ( 1<br />
2 ψ) ,<br />
where ψ = kd cosθ + β is the progressive (total) pha<strong>se</strong> shift. Specify the condition for β<br />
for a<br />
i) broadside array; ii) end-fire-array; iii) pha<strong>se</strong>d (or scann<strong>in</strong>g) array. (2p)<br />
c) A half-wavelength dipole has the <strong>in</strong>put impedance (73 + j42.5) Ω. What is the <strong>in</strong>put<br />
impedance of a quarter-wavelength monopole placed directly above an <strong>in</strong>f<strong>in</strong>ite perfect<br />
electric conductor?<br />
(1p)<br />
d) A folded half-wavelength dipole has an <strong>in</strong>put resistance of approximately<br />
i) 50 Ω; ii) 75 Ω; iii) 150 Ω; iv) 300 Ω; v) 600 Ω (1p)<br />
2. Consider a very th<strong>in</strong> f<strong>in</strong>ite length dipole of length l which is symmetrically positioned about<br />
the orig<strong>in</strong> with its length directed along the z axis accord<strong>in</strong>g to the figure. In the far-field region<br />
the condition that the maximum pha<strong>se</strong> error should be less than π/8 def<strong>in</strong>es the <strong>in</strong>ner boundary<br />
of that region to be r = 2l 2 /λ. For r ≤ 2l 2 /λ, we are <strong>in</strong> the radiat<strong>in</strong>g near-field region and<br />
the far-field approximation is not valid. By allow<strong>in</strong>g a maximum pha<strong>se</strong> error of less than π/8,<br />
show that the <strong>in</strong>ner boundary of this region is at r = 0.62 √ l 3 /λ .<br />
H<strong>in</strong>t: The vector potential is given by<br />
A = µ 4π<br />
∫<br />
I e (x ′ ,y ′ ,z ′ e−<br />
jkR<br />
)<br />
R dl′ .<br />
Expand R, where the higher order terms become more important as the distance to the antenna<br />
decrea<strong>se</strong>s. Note that r ′ = z ′ ẑ.<br />
l/2<br />
r<br />
z<br />
θ<br />
R<br />
r<br />
y<br />
x<br />
φ<br />
−l/2<br />
Cont<strong>in</strong>ued. P.t.o.→<br />
1
3. An <strong>in</strong>f<strong>in</strong>itesimal horizontal electric dipole of length l and constant electric current I 0 is placed<br />
parallel to the y axis a height h = λ/2 above an <strong>in</strong>f<strong>in</strong>ite electric ground plane.<br />
a) F<strong>in</strong>d the spherical E- and H-field components radiated by the dipole <strong>in</strong> the far-zone.<br />
b) F<strong>in</strong>d the angles of all the nulls of the total field.<br />
4. A four-element uniform array has its elements placed along the z axis with distance d = λ/2<br />
between them accord<strong>in</strong>g to the figure below.<br />
a) Derive the array factor and show that it can be written as s<strong>in</strong>(2ψ) , where ψ is the<br />
s<strong>in</strong>(ψ/2)<br />
progressive pha<strong>se</strong> shift between the elements.<br />
b) In order to obta<strong>in</strong> maximum radiation along the direction θ = 0 ◦ , where θ is measured<br />
from the positive z axis, determ<strong>in</strong>e the progressive pha<strong>se</strong> shift ψ.<br />
c) F<strong>in</strong>d all the nulls of the array factor.<br />
z<br />
d<br />
d<br />
y<br />
x<br />
d<br />
5. Two identical constant current loops with radius a are placed a distance d apart accord<strong>in</strong>g to<br />
the figure below. Determ<strong>in</strong>e the smallest radius a and the smallest <strong>se</strong>paration d so that nulls are<br />
formed <strong>in</strong> the directions θ = 0 ◦ , 60 ◦ , 90 ◦ , 120 ◦ , and 180 ◦ , where θ is the angle measured from<br />
the positive z axis.<br />
z<br />
d<br />
a<br />
y<br />
x<br />
a<br />
6. Design a l<strong>in</strong>ear array of isotropic elements placed along the z axis such that the nulls of the<br />
array factor occur at θ = 60 ◦ , θ = 90 ◦ , and θ = 120 ◦ . Assume that the elements are spaced a<br />
distance d = λ/4 apart and that β = 45 ◦ .<br />
a) Sketch and label the visible region on the unit circle.<br />
b) F<strong>in</strong>d the required number of elements.<br />
c) Determ<strong>in</strong>e the excitation coefficients.<br />
H<strong>in</strong>t: The array factor of an N-element l<strong>in</strong>ear array is given by AF =<br />
ψ = kd cos θ + β. U<strong>se</strong> the repre<strong>se</strong>ntation z = e jψ .<br />
N<br />
∑ a n e j(n−1)ψ , where<br />
n=1<br />
2