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Exam in Antenna Theory - Space.irfu.se

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<strong>Exam</strong> <strong>in</strong> <strong>Antenna</strong> <strong>Theory</strong><br />

Time: 18 March 2010, at 8.00–13.00.<br />

Location: Polacksbacken, Skrivsal<br />

You may br<strong>in</strong>g: Laboratory reports, pocket calculator, English dictionary, Råde-Westergren: “Beta”,<br />

Nordl<strong>in</strong>g-Österman: “Physics Handbook”, or comparable handbooks.<br />

Six problems, maximum five po<strong>in</strong>ts each, for a total maximum of 30 po<strong>in</strong>ts.<br />

1. a) If the complex electric field is denoted E(r), f<strong>in</strong>d the correspond<strong>in</strong>g <strong>in</strong>stantaneous (timedependent)<br />

electric field E(r,t).<br />

(1p)<br />

b) The array factor of a N-element uniform array can be written<br />

AF = s<strong>in</strong>( N<br />

2 ψ)<br />

s<strong>in</strong> ( 1<br />

2 ψ) ,<br />

where ψ = kd cosθ + β is the progressive (total) pha<strong>se</strong> shift. Specify the condition for β<br />

for a<br />

i) broadside array; ii) end-fire-array; iii) pha<strong>se</strong>d (or scann<strong>in</strong>g) array. (2p)<br />

c) A half-wavelength dipole has the <strong>in</strong>put impedance (73 + j42.5) Ω. What is the <strong>in</strong>put<br />

impedance of a quarter-wavelength monopole placed directly above an <strong>in</strong>f<strong>in</strong>ite perfect<br />

electric conductor?<br />

(1p)<br />

d) A folded half-wavelength dipole has an <strong>in</strong>put resistance of approximately<br />

i) 50 Ω; ii) 75 Ω; iii) 150 Ω; iv) 300 Ω; v) 600 Ω (1p)<br />

2. Consider a very th<strong>in</strong> f<strong>in</strong>ite length dipole of length l which is symmetrically positioned about<br />

the orig<strong>in</strong> with its length directed along the z axis accord<strong>in</strong>g to the figure. In the far-field region<br />

the condition that the maximum pha<strong>se</strong> error should be less than π/8 def<strong>in</strong>es the <strong>in</strong>ner boundary<br />

of that region to be r = 2l 2 /λ. For r ≤ 2l 2 /λ, we are <strong>in</strong> the radiat<strong>in</strong>g near-field region and<br />

the far-field approximation is not valid. By allow<strong>in</strong>g a maximum pha<strong>se</strong> error of less than π/8,<br />

show that the <strong>in</strong>ner boundary of this region is at r = 0.62 √ l 3 /λ .<br />

H<strong>in</strong>t: The vector potential is given by<br />

A = µ 4π<br />

∫<br />

I e (x ′ ,y ′ ,z ′ e−<br />

jkR<br />

)<br />

R dl′ .<br />

Expand R, where the higher order terms become more important as the distance to the antenna<br />

decrea<strong>se</strong>s. Note that r ′ = z ′ ẑ.<br />

l/2<br />

r<br />

z<br />

θ<br />

R<br />

r<br />

y<br />

x<br />

φ<br />

−l/2<br />

Cont<strong>in</strong>ued. P.t.o.→<br />

1


3. An <strong>in</strong>f<strong>in</strong>itesimal horizontal electric dipole of length l and constant electric current I 0 is placed<br />

parallel to the y axis a height h = λ/2 above an <strong>in</strong>f<strong>in</strong>ite electric ground plane.<br />

a) F<strong>in</strong>d the spherical E- and H-field components radiated by the dipole <strong>in</strong> the far-zone.<br />

b) F<strong>in</strong>d the angles of all the nulls of the total field.<br />

4. A four-element uniform array has its elements placed along the z axis with distance d = λ/2<br />

between them accord<strong>in</strong>g to the figure below.<br />

a) Derive the array factor and show that it can be written as s<strong>in</strong>(2ψ) , where ψ is the<br />

s<strong>in</strong>(ψ/2)<br />

progressive pha<strong>se</strong> shift between the elements.<br />

b) In order to obta<strong>in</strong> maximum radiation along the direction θ = 0 ◦ , where θ is measured<br />

from the positive z axis, determ<strong>in</strong>e the progressive pha<strong>se</strong> shift ψ.<br />

c) F<strong>in</strong>d all the nulls of the array factor.<br />

z<br />

d<br />

d<br />

y<br />

x<br />

d<br />

5. Two identical constant current loops with radius a are placed a distance d apart accord<strong>in</strong>g to<br />

the figure below. Determ<strong>in</strong>e the smallest radius a and the smallest <strong>se</strong>paration d so that nulls are<br />

formed <strong>in</strong> the directions θ = 0 ◦ , 60 ◦ , 90 ◦ , 120 ◦ , and 180 ◦ , where θ is the angle measured from<br />

the positive z axis.<br />

z<br />

d<br />

a<br />

y<br />

x<br />

a<br />

6. Design a l<strong>in</strong>ear array of isotropic elements placed along the z axis such that the nulls of the<br />

array factor occur at θ = 60 ◦ , θ = 90 ◦ , and θ = 120 ◦ . Assume that the elements are spaced a<br />

distance d = λ/4 apart and that β = 45 ◦ .<br />

a) Sketch and label the visible region on the unit circle.<br />

b) F<strong>in</strong>d the required number of elements.<br />

c) Determ<strong>in</strong>e the excitation coefficients.<br />

H<strong>in</strong>t: The array factor of an N-element l<strong>in</strong>ear array is given by AF =<br />

ψ = kd cos θ + β. U<strong>se</strong> the repre<strong>se</strong>ntation z = e jψ .<br />

N<br />

∑ a n e j(n−1)ψ , where<br />

n=1<br />

2

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