Stoichiometry PowerPoint

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Try One on Your Own • How many liters of CO gas will be required to make the same 10.0g of Fe? • 10.0g Fe (1 mol/55.8g) = 0.179 mol Fe • 0.179 mol Fe (3 mol CO/2 mol Fe) = 0.268 mole CO • 0.268 mol CO (22.4 L/mol) = 6.00 L of CO
Simplify • As you become more practiced at the 3 step stoichiometry problems, you can combine all the steps into 1 equation. • The last problem looks like this: • 10.0g Fe 1 mol Fe 3 mol CO 22.4 L CO = 55.8 g Fe 2 mol Fe 1 mol CO • 6.00 L CO
Page 1 and 2: Stoichiometry Connecting Mathematic
Page 3 and 4: Understanding Stoichiometry • Hyd
Page 5 and 6: Understanding Stoichiometry • How
Page 7 and 8: The Magic of Avogadro’s Number
Page 9 and 10: Conservation of Mass • All of the
Page 11 and 12: Mg + F 2 MgF 2 • Did your drawin
Page 13 and 14: 4 Al + 3 O 2 2 Al 2 O 3 • Partic
Page 15 and 16: Mass Ratios • Determining mass ra
Page 17 and 18: Now The Fun Begins • Once you kno
Page 19 and 20: Mole Ratio • Three times as much
Page 21 and 22: Solving Stoichiometry Problems •
Page 27 and 28: Examples • Let’s try a couple o
Page 29 and 30: Examples • If we start with 50.0g
Page 31 and 32: Curve Ball • Starting with the sa
Page 33: Try One on Your Own • Fe 2 O 3 +

Stoichiometry PowerPoint

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