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Stoichiometry PowerPoint

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• Fe 2 O 3 + 3 CO(g) 2 Fe + 3 CO 2<br />

• How many grams of Fe 2 O 3 will be needed to<br />

make 10.0g of Fe?<br />

• 10.0g Fe (1 mol/55.8g) = 0.179 mol Fe<br />

• 0.179 mol Fe (1 mol Fe 2 O 3 /2 mol Fe) =<br />

0.0895 mol Fe 2 O 3<br />

• 0.0895 mol Fe 2 O 3 (159.6g/mol) = 14.3g Fe 2 O 3

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