o_195h4n6al16jb186b1b2qs7fgssa.pdf

dsPIC
®
Language Tools Libraries
DS51456B-page 304
strcpy(buf1, buf3);
2004 Microchip Technology Inc.
printf("buf1 after strcpy of buf3: \n\t%s\n",
buf1);
}
Output:
buf1 : We're here
buf2 : Where is the time?
buf3 : Why?
buf1 after strcpy of buf2:
Where is the time?
buf1 after strcpy of buf3:
Why?
strcspn
Description: Calculate the number of consecutive characters at the beginning of
a
string that are not containedin a set of characters.
Include:
Prototype: size_t strcspn(const char *s1, const char *s2);
Arguments: s1 pointer to the string to be searched
s2 pointer to characters to search for
Return Value: Returns the length of the segment in s1not containing characters
found in s2.
Remarks: This function will determine the numberof consecutive characters
from
the beginning of s1that are not contained in s2.
Example: #include /* for strcspn */
#include /* for printf */
int main(void)
{
char str1[20] = "hello";
char str2[20] = "aeiou";
char str3[20] = "animal";
char str4[20] = "xyz";
int res;
res = strcspn(str1, str2);
printf("strcspn(\"%s\", \"%s\") = %d\n",
Ví dụ: # include / * Cho strncat, strlen * /
# include / * Cho printf * /
int main (void)
{
char buf1 [50] = "Chúng tôi ở đây";
char buf2 [50] = "đâu là thời điểm";
char buf3 [50] = "Tại sao?";
strlen (Tiếp theo)
Thư viện chuẩn C với hàm toán học
2004 Microchip Technology Inc DS51456B trang 307
printf ("buf1:% s \ n", buf1);
printf ("\ t (% d ký tự) \ n \ n", strlen (buf1));
printf ("buf2:% s \ n", buf2);
printf ("\ t (% d ký tự) \ n \ n", strlen (buf2));
printf ("buf3:% s \ n", buf3);
printf ("\ t (% d ký tự) \ n \ n \ n", strlen (buf3));
strncat (buf1, buf2, 6);
printf ("buf1 sau strncat 6 ký tự"
"Của buf2: \ n \ t% s \ n", buf1);
printf ("\ t (% d ký tự) \ n", strlen (buf1));
printf ("\ n");
strncat (buf1, buf2, 25);
printf ("buf1 sau strncat 25 ký tự"
"Của buf2: \ n \ t% s \ n", buf1);
printf ("\ t (% d ký tự) \ n", strlen (buf1));
printf ("\ n");
strncat (buf1, buf3, 4);
printf ("buf1 sau strncat của 4 nhân vật"
"Của buf3: \ n \ t% s \ n", buf1);
printf ("\ t (% d ký tự) \ n", strlen (buf1));
}
Đầu ra:
buf1: Chúng tôi ở đây
(10 ký tự)
buf2: đâu là thời gian?
(18 ký tự)
buf3: Tại sao?
(4 ký tự)
buf1 sau strncat 6 ký tự của buf2: