o_195h4n6al16jb186b1b2qs7fgssa.pdf

printf("\n");
printf("memset(\"%s\", \'%c\',10);\n", buf2, ch2);
memset(buf2, ch2, 10);
printf("buf2 aftermemset: %s\n", buf2);
}
Output:
memset("What time isit?", '?',4);
buf1 after memset: ???? time is it?
memset("", 'y',10);
buf2 after memset: yyyyyyyyyy
dsPIC
®
Language Tools Libraries
DS51456B-page 300
strcat
2004 Microchip Technology Inc.
Description: Appends a copy of the source stringto the end of the destination
string.
Include:
Prototype: char *strcat(char *s1, const char *s2);
Arguments: s1 null terminated destination string to copy to
s2 null terminated source string to be copied
Return Value: Returns a pointer to the destination string.
Remarks: This function appends the source string (including the terminating
null
character) to the end of the destination string. The initial character of
the source string overwrites the null character at the end of the
destination string. If the buffers overlap, the behavior is undefined.
Example: #include /* for strcat, strlen */
#include /* for printf */
int main(void)
{
char buf1[50] = "We're here";
char buf2[50] = "Where is the time?";
printf("buf1 : %s\n", buf1);
printf("\t(%d characters)\n\n", strlen(buf1));
printf("buf2 : %s\n", buf2);
printf("\t(%d characters)\n\n", strlen(buf2));
strcat(buf1, buf2);
printf("buf1 after strcat of buf2: \n\t%s\n",
buf1);
printf ("\ n");
res = strcmp (buf1, buf3);
if (res