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Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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3.4 Generalized first-order kinetics* 51<br />

• Conclusions:<br />

(1) The largest (negative) eigenvalue ( 2 in this case) determines the shortest<br />

time scale and thus the short-time evolution of the reactant concentrations!<br />

(2) The smallest (negative) eigenvalue ( 1 in this case) determines the longest<br />

time scale of the reaction, i.e., the evolution of the reactant concentrations<br />

at long times. The smallest (negative) eigenvalue thus determines the net<br />

reaction rate!<br />

(3) Note that in the example the concentrations at long times are constant<br />

(equilibrium!) and therefore 1 =0.<br />

• Evaluation of the eigenvectors p 1 und p 2 by inserting the eigenvalues { 1 2 }<br />

one by one into<br />

K · P = Λ · P (3.81)<br />

yields, for each and the respective p , a linear equation of the type<br />

K · p = · p (3.82)<br />

y<br />

y<br />

(K − ) · p =0 (3.83)<br />

(− 1 − ) 1 + 2 2 =0 (3.84)<br />

1 1 +(− 2 − ) 2 =0 (3.85)<br />

• Inserting 1 =0:<br />

− 1 1 + 2 2 =0 (3.86)<br />

1 1 + − 2 2 =0 (3.87)<br />

y<br />

y<br />

1 1 = 2 2 (3.88)<br />

1 = 2 · (3.89)<br />

2 = 1 · (3.90)<br />

y<br />

• Inserting 2 = − ( 1 + 2 ):<br />

p 1 =<br />

µ <br />

2 · <br />

1 · <br />

(3.91)<br />

(− 1 + 1 + 2 ) 1 + 2 2 =0 (3.92)<br />

1 1 +(− 2 + 1 + 2 ) 2 =0 (3.93)<br />

y<br />

2 1 + 2 2 =0 (3.94)<br />

1 1 + 1 2 =0 (3.95)

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