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Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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3.2 Application of the steady-state assumption 45<br />

3.2.2 Further examples<br />

I<br />

I<br />

Exercise 3.1: The thermal decomposition of acetaldehyde according to the overall<br />

reaction<br />

CH 3 CHO → CH 4 +CO (3.31)<br />

is known to proceed via the following elementary steps (Rice-Herzfeld mechanism):<br />

CH 3 CHO → CH 3 +HCO (1)<br />

CH 3 +CH 3 CHO → CH 4 +CH 3 CO (2)<br />

(3.32)<br />

CH 3 CO → CH 3 +CO (3)<br />

CH 3 +CH 3 → C 2 H 6 (4)<br />

Derive an expression for the production rate of [CH 4 ]. (Hint: Use the steady-state<br />

approximations for [CH 3 CO] and [CH 3 ] and neglect the HCO for the derivation of the<br />

expression.) ¤<br />

A more complete mechanism takes into account the thermal decomposition of the HCO<br />

radicals according to HCO → H + CO (5) followed by the reaction H + CH 3 CHO →<br />

H 2 +CH 3 CO (6).<br />

Solution 3.1: With the steady state approximations for [CH 3 CO] and [CH 3 ],weobtain<br />

[CH 3 CO]<br />

<br />

= 2 [CH 3 ][CH 3 CHO] − 3 [CH 3 CO] ≈ 0 (3.33)<br />

y [CH 3 CO] <br />

= 2 [CH 3 ][CH 3 CHO]<br />

3<br />

(3.34)<br />

and<br />

y<br />

[CH 3 ]<br />

<br />

= 1 [CH 3 CHO] − 2 [CH 3 ][CH 3 CHO] (3.35)<br />

+ 3 [CH 3 CO] − 2 4 [CH 3 ] 2 (3.36)<br />

= 1 [CH 3 CHO] − 2 [CH 3 ][CH 3 CHO] (3.37)<br />

+ 3 2 [CH 3 ][CH 3 CHO]<br />

− 2 4 [CH 3 ] 2<br />

3<br />

(3.38)<br />

= 1 [CH 3 CHO] − 2 4 [CH 3 ] 2 ≈ 0 (3.39)<br />

µ 12 1 [CH 3 CHO]<br />

y [CH 3 ] <br />

=<br />

(3.40)<br />

2 4<br />

[CH 4 ]<br />

<br />

[CH 4 ]<br />

<br />

= 2 [CH 3 ][CH 3 CHO]<br />

= 2<br />

µ<br />

1<br />

2 4<br />

<br />

[CH 3 CHO] 32 (3.41)<br />

¥<br />

I Exercise 3.2: The thermal decomposition of ethane gives mainly H 2 +C 2 H 4 . In<br />

addition, small amounts of CH 4 are formed. The decay of the C 2 H 6 concentration can<br />

be described by the reaction steps<br />

C 2 H 6 → CH 3 +CH 3 (1)<br />

CH 3 +C 2 H 6 → CH 4 +C 2 H 5 (2)<br />

C 2 H 5 → C 2 H 4 +H (3)<br />

(3.42)<br />

H+C 2 H 6 → C 2 H 5 +H 2 (4)<br />

H+C 2 H 5 → C 2 H 6 (5)

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