Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ... Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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2.4 Kinetics of second-order reactions 25 I Figure 2.9: Kinetics of second-order reactions. I Half lifetime: y y y £ A ¡ 12 ¢¤ = [A] 0 2 (2.87) 2 [A] 0 = 1 [A] 0 +2 12 (2.88) 12 = 1 2 [A] 0 (2.89) The half lifetime for a second-order reactions depends on the initial concentration! 2.4.2 A + B → products A+B→ P (2.90)

2.4 Kinetics of second-order reactions 26 I Solution of the rate equation: − [A] = − [B] = [A] [B] (2.91) (1) Substitution: =([A] 0 − [A] )=([B] 0 − [B] ) (2.92) [A] = [A] 0 − (2.93) y = ([A] 0 − )([B] 0 − ) (2.94) (2) Integration using partial fractions (skipped here): (3) General solution: [B] 0 [A] [A] 0 [B] =exp([A] 0 − [B] 0 ) (2.95) 2.4.3 Pseudo first-order reactions In experimental studies of second-order reactions of the type A+B→ C, onelikesto use a high excess of one of the reactions partners (e.g., [B] À [A]) sothat[B] ≈ const Under this condition, the reaction is said to be pseudo first-order, because [B] = 0 (2.96) y Solution of [A ()]: [A] = [A] 0 −0 =[A] 0 −[B] (2.97) I Experimental investigation of pseudo first-order reactions: (1) Measurements of the pseudo first-order decay of [A] vs. at different concentrations of [B]: Plotofln [A] vs. give pseudo first-order rate constant 0 = [B] for each value of [B]. (2) Plot of 0 = [B] vs. [B] gives straight line with slope . ⇒ We do not need the absolute concentration of [A], only the concentration of [B] is needed.

2.4 <strong>Kinetics</strong> of second-order reactions 26<br />

I<br />

Solution of the rate equation:<br />

− [A]<br />

<br />

= − [B]<br />

<br />

= [A] [B] (2.91)<br />

(1) Substitution:<br />

=([A] 0<br />

− [A] <br />

)=([B] 0<br />

− [B] <br />

) (2.92)<br />

[A] = [A] 0<br />

− (2.93)<br />

y<br />

<br />

= ([A] 0 − )([B] 0<br />

− ) (2.94)<br />

(2) Integration using partial fractions (skipped here):<br />

(3) General solution:<br />

<br />

[B] 0<br />

[A] <br />

[A] 0<br />

[B] <br />

=exp([A] 0<br />

− [B] 0<br />

) (2.95)<br />

2.4.3 Pseudo first-order reactions<br />

In experimental studies of second-order reactions of the type A+B→ C, onelikesto<br />

use a high excess of one of the reactions partners (e.g., [B] À [A]) sothat[B] ≈ const<br />

Under this condition, the reaction is said to be pseudo first-order, because<br />

[B] = 0 (2.96)<br />

y Solution of [A ()]:<br />

[A] = [A] 0<br />

−0 =[A] 0<br />

−[B] (2.97)<br />

I<br />

Experimental investigation of pseudo first-order reactions:<br />

(1) Measurements of the pseudo first-order decay of [A] vs. at different concentrations<br />

of [B]: Plotofln [A] vs. give pseudo first-order rate constant 0 = [B]<br />

for each value of [B].<br />

(2) Plot of 0 = [B] vs. [B] gives straight line with slope .<br />

⇒ We do not need the absolute concentration of [A], only the concentration of [B] is<br />

needed.

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